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3 years ago

10

For a field trip, the school bought 47 sandwiches for $4.60 each and 39 bags of chips for $1.25 each. How much did the school sp

end in all?

2 answers:

NNADVOKAT [17]3 years ago

8 0

Answer: $\$264.95$

Step-by-step explanation:

You know that 1 sandwich costs $4.60 and the school bought 47 sandwiches.

Therefore, in order to calculate the total cost of 47 sandwiches, you need to multiply this number of sandwiches bought by the schoole, by the cost of 1 sandwich. Then:

$sandwiches=(47)(\$4.60)\\\\sandwiches=\$216.2$

You know that 1 bag of chip costs $1.25 and the school bought 39 bags of chips.

So, in order to calculate the total cost of 39 bags of chips, you must multiply the total number of them bought by the school, by the cost of 1 bag of chips.

Then:

$bag\ of\ chips=(39)(\$1.25)\\\\bag\ of\ chips=\$48.75$

Therefore, the total amount school spent was:

$Total\ spent=\$216.2+\$48.75\\\\Total\ spent=\$264.95$

dmitriy555 [2]3 years ago

7 0

Multiply the price per each by the quantity of each:

Sandwiches: 4.60 x 47 = $216.20

Chips: 1.25 x 39 = $48.75

Total spent = 216.20 + 48.75 = $264.95

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3 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

a

The 95% confidence interval is $0.0503 < p < 0.1297$

b

The sample proportion is $\r p = 0.09$

c

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

d

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

3 years ago

The width of a rectangle is 12 inches more than the length. The perimeter is 76 inches. Find the width and the length.

stira [4]

Answer:

The length of the rectangle is 13 inches and its width (13 + 12) is 25 inches.

Step-by-step explanation:

You have to consider the formula of the perimeter = 2·length + 2·width.

If we call "x" to the length ⇒ width = x + 12 .

Perimeter = 2x + 2·(x + 12) ⇒ Perimeter = 2x + 2x + 24

⇒Perimeter = 4x + 24. ⇒ 76 = 4x + 24 ⇒ 76 - 24 = 4x ⇒52 = 4x

⇒ 52/4 = x ⇒ x = 13.

So, the length of the rectangle is 13 inches and its width (13 + 12) is 25 inches.

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Answer:

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Step-by-step explanation:

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