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2 years ago

I need help with my dilation paper!

Mathematics

1 answer:

marusya05 [52]2 years ago

3 0

Dilation is a smaller version of the original shape. you are mutilping the coordinates given by 1/2

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The relationship between feet and inches is described by the equation y = 12x, where x = a given length in feet and y = the equi

Westkost [7]

The answer is B, 75 inches. This is because for every for there is 12 inches. So, if you plug in 6.25 where the x is, it is saying there are 12 inches per 6.25 feet. So multiply 12 by 6.25 to get 75, your answer, B. Hope this helps

8 0

2 years ago

Fine the sum of 2/9+3/5

Arturiano [62]

Answer:

0.82

اولويات الضرب و القسمه

6 0

2 years ago

PLEASE HELPP

agasfer [191]

Answer:

The solution to the system of equations be:

$x=3,\:y=-1$

Hece, option B is correct.

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}x-3y=6\\ 2x+2y=4\end{bmatrix}$

Multiply x − 3y = 6 by 2: 2x-6y=12

$\begin{bmatrix}2x-6y=12\\ 2x+2y=4\end{bmatrix}$

$2x+2y=4$

$-$

$\underline{2x-6y=12}$

$8y=-8$

so the system of equations becomes

$\begin{bmatrix}2x-6y=12\\ 8y=-8\end{bmatrix}$

Solve 8y = -8 for y

$8y=-8$

Divide both sides by 8

$\frac{8y}{8}=\frac{-8}{8}$

$y=-1$

$\mathrm{For\:}2x-6y=12\mathrm{\:plug\:in\:}y=-1$

$2x-6\left(-1\right)=12$

$2x+6=12$

subtract 6 from both sides

$2x+6-6=12-6$

$2x=6$

Divide both sides by 2

$\frac{2x}{2}=\frac{6}{2}$

$x=3$

Therefore, the solution to the system of equations be:

$x=3,\:y=-1$

Hence, option B is correct.

6 0

2 years ago

Read 2 more answers

The relative frequency distribution of the number of phobias reported by a hypothetical sample of 500 college students is given

goldenfox [79]

Answer:

a. 0.48

b. 0.14

c. 0.47

Step-by-step explanation:

Data provided in the question

0 - 2 0.48

3 - 5 0.26

6 - 8 0.12

9- 11 0.09

12- 14 0.05

Based on the above information

a. The probability for fewer than three phobias is

= P( x < 3)

= 0.48

b. The probability for more than eight phobias is

= P( x >8)

= 0.09 + 0.05

= 0.14

c. Probability between 3 and 11 phobias is

= P(3 < x < 11)

= 0.26 + 0.12 + 0.09

= 0.47

3 0

3 years ago

Find the area of the shaded region

Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

$\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm$

where $h$ is the length of the altitude originating from vertex O, and so

$\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm$

where $b$ is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

7 0

1 year ago