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navik [9.2K]
3 years ago
9

There is a daily fee for renting a moving truck, plus a charge of $0.50 per mile driven. If driven 48 miles, it costs $64 to ren

t a truck. Write and solve an equation to find the daily fee.
Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0
Let x be the daily fee
0.5(48) +x = 64  is the equation, 
Multiply:
24 + x = 64
Subtract:
 x=40
The daily fee is $40
Hope this helps

Delicious77 [7]3 years ago
3 0
Let x be the daily fee
0.5(48) +x = 64  is the equation, 
Multiply:
24 + x = 64
Subtract:
 x=40
The daily fee is $40
Hope this helps

Credit to Bob3141 (My first answer was wrong)
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An airplane travel at a constant speed of 575 miles per hour.write and equation that can be used to determine the number of mile
Oxana [17]

Answer:

m = 575h

Step-by-step explanation:

Given

Rate = 575 miles/hour

Required

Determine the equation for the model

Represent the number of hours with h and the miles with m.

Using distance formula:

Distance = Speed * Time

In this case, it is:

Miles = Rate * Hour

So, we have:

m = 575 * h

m = 575h

3 0
2 years ago
The population of Weston is 4320. The town’s records show that 45 percent of the population are males, and 2 3 23 of these males
lbvjy [14]

Answer:

In Weston 1,296 males are married

Step-by-step explanation:

step 1

Find out the number of males

Multiply the total population by 45%

45\%=45/100=0.45

4,320(0.45)=1,944\ males

step 2

Find out the number of males that are married

Multiply the number of males by 2/3

\frac{2}{3}(1,944)=1,296\ males\ married

therefore

In Weston 1,296 males are married

7 0
3 years ago
The mean of 10 values is 19. If further 5 values are
Leokris [45]

Answer:

22

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is  a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300                since 15(20)=300

Now let's look at the first 10:  We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190                               since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

      k+l+m+n+o=300-190

      k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0
3 years ago
Can anyone help with this math problem?
Ne4ueva [31]
The answer is 8. You rewrite the fraction as 5.25.
6 0
2 years ago
Read 2 more answers
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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