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alina1380 [7]
3 years ago
12

-5d+(-6)u-3, when d=2 and u =7

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0
-5d+(-6)u-3= -5*2-6*7-3= -10 - 42-3= -55

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What is the domain of the exponential function f(x) = 3 ^ x - 5
kozerog [31]

Answer:

(-infinity, infinity)

Step-by-step explanation:

7 0
3 years ago
Please help!! It would be much appreciated!
Alexxx [7]

Answer:

Power property for both

Step-by-step explanation:

The power property of logarithms says that if there is an exponent in a logarithm, then that exponent can be pulled to the front.

In the first question, 5 is at the front of the logarithm because it has been pulled from 3. If you move the 5 back to the 3, it would be 3^5, which is 243.

In the second question, 2 is at the front of the logarithm as it has been pulled from the 9. If you move the 2 back to the 9, it would be 9^2, or 81.

Example:

log10^2 would be equal to 2log10.

3 0
3 years ago
5.(03.06)
maw [93]

Answer:

y = 3 \div 4x + 10

6 0
3 years ago
Solve the system by the substitution method.<br> 2x-y= -24<br> x+7y= 3
meriva
2x - y = -24
x + 7y = 3

Solve one equation for a variable and plug the resulting value into the second equation.

x + 7y = 3           Subtract 7y from both sides
       x = -7y + 3

Now, plug that x-value into the x of the first equation.

            2x - y = -24   Plug in the x-value
2(-7y + 3) - y = 24     Use the Distributive Property
  -14y + 6 - y = -24     Combine like terms (-14y and -y)
       -15y + 6 = -24     Subtract 6 from both sides
             -15y = -30     Divide both sides by 15
                  y = 2

Next, plug the y-value back into the second equation.

  x + 7y = 3      Plug in the y-value
x + 7(2) = 3     Multiply
   x + 14 = 3     Subtract 14 from both sides
          x = -11

y = 2 and x = -11
6 0
3 years ago
Mrs. Long just got a new puppy! The puppy is learning how to run on hard wood floors. The puppy is running at a rate if 4 feet p
Luba_88 [7]

Answer:

Points apply to the given situation:

(a)The puppy will run into the wall after 5 seconds

(b)The slope is -4 ft per second since the puppy is running at a rate of 4 ft per second.

(c)The y-intercept is 20 ft because the puppy is 20 feet away from the wall.

Step-by-step explanation:

We have given,

A puppy is running at a rate = 4 feet per second

A wall is 20 feet away from puppy. That means initially puppy is 20 feet away from the wall.

So, time taken by puppy to reach the wall = \frac{Distance}{rate}

i.e. time take by puppy to reach the wall = \frac{20}{4} = 5 seconds

 Now we write the points that apply to this situation:

(a)The puppy will run into the wall after 5 seconds

(b)The slope is -4 ft per second since the puppy is running at a rate of 4 ft per second. {Since the puppy is moving towards the wall that means horizontal distance is decreasing at a rate of -4 feet per second}

(c)The y-intercept is 20 ft because the puppy is 20 feet away from the wall.

7 0
4 years ago
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