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3 years ago

Which of the following is a perfect square? A)154 B)169 C)279 D)115

Mathematics

2 answers:

morpeh [17]3 years ago

7 0

A) 154 because it's an even number

slamgirl [31]3 years ago

6 0

Answer:

Step-by-step explanation:

Multiply two of the same will give you a perfect square like 13 x 13 is 169

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There are a total of 63 bikes if the ratio of blue bikes and black bikes is 45 how many are blue?

maw [93]

18 blue bikes. 63 - 45 = 18

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3 years ago

Jeremy used 11 gallons and 3 quarts of water to water his garden. How many quarts of water did Jeremy use?

Anon25 [30]

Answer:

Step-by-step explanation:

since each gallon is 4 quarts you would multiply by 11. 44 quarts then add 3 extra quarts to get 47

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3 years ago

The sphere weighs 4 pounds. sorry no picture but you can ask me for it in the comments What is the weight of the cylinder? What

Zolol [24]

Answer:

The weight is 4 pounds :D

Step-by-step explanation:

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3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago

9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent

Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

$x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\ = 1156 + 1156 - 2312 cos 138\\ = 4030.150837...\\x = \sqrt{4030.150837} = 63.48$ $x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\ = 1156 + 1156 - 2312 cos 138\\ = 4030.1508...\\ x = \sqrt{4030.1508} \\ = 63.48$ x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

= 1156 + 1156 - 2312 c0s 138

= 4030.1508...

x = sq rt 4030.1508...

= 63.5

7 0

3 years ago