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lara [203]
4 years ago
14

Heath took $40 to the mall. So far, he has purchased a baseball cap for $16.75. Write and solve an inequality to determine how m

uch more money Heath can spend.
Help! I don’t know how :/
Mathematics
2 answers:
yan [13]4 years ago
7 0
40 - 16.75 = how much he has
Tom [10]4 years ago
7 0

Correct Answer: d ≤ 23.25

16.75 + d ≤ 40 (d stands for dollars. we don't know what number d stands for yet, so we need to figure it out. We know that he can spend no more than $40, so that is why the "≤" sign is there. He can either spend equal to $40 or less than $40 is what the "≤" sign is saying.)

So if the total money Heath can spend is $40 and he's already spent $16.75, then we just find out how much money is left that he can spend.

You have to subtract 16.75 from both sides of the less than or equal to sign (≤). 16.75 minus 16.75 equals zero. 40 minus 16.75 equals 23.25.

So now we have: d ≤ 23.25 . That is the answer.

Sorry that took FOREVER. I had to make sure it was correct.

Answer: d ≤ 23.25

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Have a great day!

6 0
4 years ago
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Katyanochek1 [597]

Answer:

1

Step-by-step explanation:

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here the dots that belong to the line that you can most easily see are:

A(-6,0)

B(0,6)

by inserting the values into the euquation you get:

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good luck with your maths solving

6 0
2 years ago
Instructions
Naya [18.7K]

Answer:

yes

Step-by-step explanation:

youre trying to find when -1/4x + 3/2 = -x+ 3

so if you set it up like that and then solve for x you get 2

then, you know that 2 is your x value so just plug in x into one of the equations to get the y value

(i used -x+3 bc its easier)

-2+3=y

y= 1

so your solution is (2,1)

also heres the graph

5 0
3 years ago
Which of the following is the height of the special trapezoid if WX = 16, YZ = 16, and the area is 80 units2?
user100 [1]
A. 5 if u divide 80 by 16 you get 5 

3 0
3 years ago
Read 2 more answers
Please help meeeeeee...
dangina [55]
Parallel means lines that never meet, and perpendicular are lines that meet at right angles.

5 0
3 years ago
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