Answer:
See below.
Step-by-step explanation:
Here's an example to illustrate the method:
f(x) = 3x^2 - 6x + 10
First divide the first 2 terms by the coefficient of x^2 , which is 3:
= 3(x^2 - 2x) + 10
Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form
(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.
= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)
= 3 [(x - 1)^2 -1 ] + 10
= 3(x - 1)^2 - 3 + 10
= <u>3(x - 1)^2 + 7 </u><------- Vertex form.
In general form the vertex form of:
ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .
This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.
Answer: critical thinking, judgement and decision making, speaking, active listening, and science
Step-by-step explanation:
I got it right.
Answer:
So, option A is correct.
Step-by-step explanation:
To find the inverse of the matrix, the formula is:
Inverse of the matrix exists if |A| does not equal to 0
|A| = 7 * 9 -( -2 * -10)
|A| = 63 - 20
|A| = 43
AS |A| ≠ 0
so inverse exist.
now finding Adj A
= ![\left[\begin{array}{cc}9&2\\10&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%262%5C%5C10%267%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}9/43&2/43\\10/43&7/43\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%2F43%262%2F43%5C%5C10%2F43%267%2F43%5Cend%7Barray%7D%5Cright%5D)
So, option A is correct.
Your answer would be A) a+c+e
a-b+c
b-c+d
c-d+e
+
——————
a+c+e
not too sure but I think your answer would be -5
