Question

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Which equation is equivalent to $(x^{2}+6)^{2}-21=4x^{2}+24$ in terms of $p$?

Answer 1

Answer:

Hello There. ☆~---~--___●♡●__~--☆ Since p = x² - 7, you can substitute/plug in p for x² - 7

So:

(x² - 7)² - 4x² + 28 = 5

(p)² - 4x² + 28 = 5   You can factor out -4 from (-4x² + 28)

p² - 4(x² - 7) = 5        Plug in p

p² - 4p = 5        Subtract 5

p² - 4p - 5 = 0  And, your correct answer is C.

Hope It Helps!~

ItsNobody~ ☆