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3 years ago

PLEASE HELP!! DUE SOON

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

7 0

Answer:

b=3a/8

a=8b/3

Step-by-step explanation:

b/a=k ( k is the constant proportional)

3/8=9/24=15/40

b/a=3/8

b=3a/8

a=8b/3

I hope this is right answer

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An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. Find the force necessary to prevent the car fro

Misha Larkins [42]

Answer:

1931.7N

Step-by-step explanation:

We are told in the question that :

An auto ( a car) weighs = 2500 pounds

It s inclined at n horizontal Ange of 10°

We are asked to find the force that would prevents it from rolling down the street.

Since the unit for Force = Newton or kgm/s²

Step 1

Convert Weight in pounds to kg

1 pound = 0.453592kg

2500 pounds =

2500 pounds × 0.453592kg

= 1133.981kg

Step 2

Find the force that would prevents it from rolling down the street.

Force = Mass × Acceleration due to gravity × sin θ

Acceleration due to gravity = 9.81m/s

Force = 1133.981kg × 9.81 × sin 10°

Force = 1931.7237321 N

Approximately = 1931.7N

4 0

3 years ago

Find the value of x y and z

poizon [28]

I think you can plus like 180 plus that or 180 minus butttt it’s bc the angle looks like a “C” so you plus

5 0

3 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

6 0

3 years ago

86 is the same as u multiplied by 206

Gala2k [10]

U would equal 206/86 or 2.39585

6 0

3 years ago

What is the volume of a cylinder with a diameter of 8 name m and a height of 5.5

Cerrena [4.2K]

To begin, you must plug all the values you have into a formula, and also putting them in the right form.

The formula for the volume of a cylinder is: πr²h

FINDING RADIUS: With this in mind, now we know that, our diameter must be converted to a radius. To do this, you divide your diameter by two. This gives you, 4 as your radius.

FINDING HEIGHT: In the question you sent, you can tell they've given you, your height, so all you need to do is plug it into the equation.

PLUGGING IT IN:

Your pi, stays the same when using a calculator, just press your pi symbol depending on the calculator you are using. Your radius is 4, therefore it wants you to square it, which is 4x4, which equals 16. Next, you want to multiply it by the height, so just multiply it with your height, 5.5

YOUR ANSWER:

276.46m

6 0

3 years ago