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Rainbow [258]
3 years ago
15

Find the midpoint of the segment below and enter its coordinates as an ordered pair. If necessary, express coordinates as fracti

ons, using the slash mark (/) for the fraction bar. (-12, -3) (3, -8)
Mathematics
1 answer:
galben [10]3 years ago
7 0

Answer:

=\left(-\frac{9}{2},\:-\frac{11}{2}\right)

Step-by-step explanation:

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-12,\:-3\right),\:\left(x_2,\:y_2\right)=\left(3,\:-8\right)\\\\=\left(\frac{3-12}{2},\:\frac{-8-3}{2}\right)\\\\=\left(-\frac{9}{2},\:-\frac{11}{2}\right)

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Which of the following equations has only one solution? x2 + 4x + 4 = 0 x2 + x = 0 x2 - 1 = 0
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4 0
2 years ago
Read 2 more answers
the cost y (in dollars) for x pounds of deli meat is represented by the equation y=3.5x, graph the equation
wel

Answer:

I don't have the graph, but I'll explain what you need to do. Plot a point with the coordinates (1,3.5), (2,7), (3,10.5), and (4,14). Now draw a straight line connecting al these pints but don't go past the origin into the negative as in this situation it is not possible. There! Now you have a graph :)

8 0
2 years ago
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5 0
3 years ago
How do you find the length of the curve x=3t−t3x=3t-t^3, y=3t2y=3t^2, where 0≤t≤3√0&lt;=t&lt;=sqrt(3) ?
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It's simple, you just have to do this:

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replacing

L=\int\limits_{0}^{\sqrt{3}}\sqrt{\left(3-3t^2\right)^2+\left(6t\right)^2}~dt

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\boxed{\boxed{L=3\sqrt{3}+3\sqrt{3}=6\sqrt{3}}}
8 0
2 years ago
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