F is proportional to 1/x^2
distance = x
A reduction of 25 percent = 0.75x
Let’s put this in place of x
F = 1/(0.75x)^2
And simplify
F = 1/0.5625x^2
So you need to find the percentage increase from 1/x^2 to 1/0.5625x^2
So what does 1/x^2 multiply by to give 1/0.5625x^2
Written as an equation it is y/x^2 = 1/0.5625x^2
Multiply both sides by x^2
y = 1/0.5625
y = 1.778 (rounded to 3 decimal points)
So the decimal multiplier is 1.778 and so the percent increase is approximately 77.8%
Answer:
(1 , -2)
Step-by-step explanation:
The intersecting point of two lines is the solution
From the graph: there are 200 students overall. For the next 100, we can divide each number by 2 to find an estimate for how many with participate in MATH tutoring. 40 divided by 2 =20 students participating in MATH tutoring.
Part B- There are currently 55 students out of 200 in SCIENCE tutoring. We add 55 more for 400 = 110, add 55 more for 600=165, and then add half of 55 (27.5 or 28 because you CANNOT have half a student) for 700 students total. 55+55+55+28=193 students.
3x2x(-4)=-24
3x2-4=2
3+2-4=1
not entirely sure what the equation your asking is but i hope this helps
Log7 36 is the correct answer.
