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3 years ago

13

Y= kx+m Make x the subject

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

Kx=y-m
x=(y-m)/k
Note that this is also standard linear form, x=y/k-m/k where slope=1/k and x intercept is -m/k.

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Hatshy [7]

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7 0

3 years ago

Add 7 x 10−6 and 2.1 x 10−5.<br><br> 9.1 x 10−6<br> 2.8 x 10−6<br> 9.1 x 10−5<br> 2.8 x 10−5

valkas [14]

The answer is 2.8 x 10-5

3 0

2 years ago

What is the factorization of the trinomial below? 3x3 + 6x2 - 24x

Allisa [31]

3x^3 + 6x^2 - 24x

= 3x(x^2 + 2x - 8)

= 3x(x + 4)(x - 2)

Hope it helps.

8 0

3 years ago

Read 2 more answers

I need help with this I will mark you brainlest if correct

liubo4ka [24]

Answer:

c

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the PERIMETER and AREA of each figure below

Oduvanchick [21]

Answer:

22)

$2(length+breadth+h)$

$2(5a^2b^2+3ab^2)$

$Perimeter: 2ab^2(5a^2+31)$

$Area:-$

$5a^2b^4 *3ab^2$

$A=15a^2b^6$

-----------

23)

$perimeter:-$

$4m^2+3mn^2+7mn$

$4m^2+10mn^2$

$answer: 2m(2m+5n^2)$

$Area:-$

$\frac{1}{2}* base* height$

$1/2*3mn^2*4m^2$

$6mx^{2+1}n^2$

$A=6m^3n^2$

----------

24)

$1/2*b*h$

$1/2x^24m^2*8mn$

$A=16m^3n$

----------

25)

$1/2*(7a^2b+11a^2b)*3ab$

$1/2*18a^2b*3ab$

$9a^2b*3ab$

$A=27 a^3b^2$

------------

26)

$A= 9\pi (x^3y)^2$

∴To calculate the perimeter , add the length of its sides.

∴To calculate the area, multiply its height by its width.

<u>------------------------</u>

hope it helps...

have a great day!!

8 0

3 years ago