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Irina18 [472]
3 years ago
12

Fewer than is right? my brain isnt working rn

Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

You should say "less than"

Step-by-step explanation:

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Please help!!!What is the average rate of change of the function on the interval from x=o to x=2? F(x)=250(0.5)^x
REY [17]

1) in first place you must Know F(X) for every value of x

F(0) = 250(0.5)^0 = 250

f(1) = 250(0,5)^1 = 250*0,5 = 125

f(2)= 250(0,5)^2= 250*0,25 = 62,5

the average is = 250+125+62,5/ 3 = 145,83

7 0
4 years ago
What are the roots of 3x2 + 10 = 4x?
sveticcg [70]

Answer:

Option C is correct.

roots of the given equation , x =\frac{2\pm i\sqrt{26}}{3}

Step-by-step explanation:

Given the equation: 3x^2+10 = 4x

We can write this equation as:

3x^2-4x + 10 =0

A quadratic equation is in the form of ax^2+bx+c =0      ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

On comparing given equation with equation [1] we get;

a = 3 , b = -4 and c =10

So, the solution of the given equation is given by;

x = \frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}

or

x =  \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}

or

x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}    [∴\sqrt{-1} = i

Simplify:

x =\frac{2\pm i\sqrt{26}}{3}

therefore, the roots of the given equation are; x =\frac{2\pm i\sqrt{26}}{3}

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3 years ago
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Which expression is equivalent to
KiRa [710]

Answer:

30 - (20 ÷ x) ⋅ 4

Step-by-step explanation:

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3 years ago
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I need the steps, I had tryed already and I have an answer key; but I do not have tut he steps. I'm also am not in school at thi
blagie [28]
The answer is C. From the solution in the picture

5 0
3 years ago
Free daily points<br><br> I do this every day around 10:00 AM est
riadik2000 [5.3K]

Answer:

hi

Step-by-step explanation:

5 0
3 years ago
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