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evablogger [386]
3 years ago
11

The vertices of quadrilateral PQRS are P(4, 5), Q(6, 6), R(9, 4), and S(7, 2). Write a paragraph proof to determine whether quad

rilateral PQRS is a parallelogram.

Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0
The vector PQ is Q-P = (2, 1). The vector SR is R-S = (2, 2). One is not a multiple of the others, so the vectors are not parallel. In a parallelogram, these vectors would be identical. PQRS is not a parallelogram.

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aksik [14]

Check the picture below.

we know that AL is an angle bisector, so the angle at A gets cuts into two equal halves, we also know the angle at B is 30°, so the triangle ABC is really a 30-60-90 triangle, meaning the angle at A is really a 60° angle, cut in two halves gives us 30° and 30° as you see in the picture.

if the angles at A and B, inside the triangle ABL, are equal, twin angles are only made in an isosceles by twin sides, that means that AL = BL.

Looking at the triangle ALC, we can see is also another 30-60-90 triangle, and we can just use the 30-60-90 rule to get x=CL.

3 0
3 years ago
HELP I REALLY NEED HELP
zepelin [54]

Answer: 72 inches squared

Step-by-step explanation:

So, the real floor of a classroom is 36 feet by 32 feet.

And the scale drawing, has length of the classroom equal to 9 inches.

What is the area in square inches of the floor in the scale drawing

1 foot = 12 inches

The length of the classroom, measured in feet, has been multiplied by 12, to get converted in inches. After that, it has been divided by a number, a proportion, to get to 9 inches.

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432 inches / x = 9 inches

Now, to solve for x, we can cross-multiply

432 inches = 9x inches

Divide 9 inches on both sides.

x = 48

To solve the exercise, we need to calculate the floor's area in the scale drawing.

We have the length = 9 inches.

Now, let's calculate the width

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Width = 8 inches

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Area = 9 inches * 8 inches

Area = 72 inches squared

Hope I helped!

6 0
2 years ago
What is the value of x in the equation<br> 4z +16<br> 12<br> = х - 4?
Serhud [2]
<h3>Solution:</h3>

\frac{4x + 16}{12}  = x - 4 \\  =  > 4x + 16 = 12(x - 4) \\  =  > 4x + 16 = 12x - 48 \\  =  > 16 + 48 = 12x  - 4x \\  =  > 64 = 8x \\  =  > x =  \frac{64}{8}  \\  =  > x = 8

<h3>Answer:</h3>

x = 8

7 0
2 years ago
A leprechaun places a magic penny under a​ girl's pillow. The next night there are 2 magic pennies under her pillow. The followi
Mars2501 [29]

Answer:

36 days

Step-by-step explanation:

Since the pennies need to be kept under the pillow in order to be doubled, we're really looking for the day the girl will wake up with 21 billions pennies under her pillow.

The general formula of that geometric sequence will be: t = 1 + 2^(n-1)

We need to find the value of n when t will be over 21,000,000,000.

So, the equation becomes:

21,000,000,001 = 1 + 2^(n-1)

2^(n-1) = 21,000,000,000

log(2^(n-1)) = log(21,000,000,000)

(n-1) * log(2) = log(21,000,000,000)

n-1 = log(21,000,000,000) / log(2)

n-1 = 34.29

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Since it has to be complete days, and we have to reach over 21 billions, then we round it up to 36.

5 0
3 years ago
A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen
Darina [25.2K]

Answer:

100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving y=x^2 about y axis in the interval 0\leq x\leq 3.

Density of the fluid in the tank, D=100\ lbs/ft^3

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, y(0)=0^2=0

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in x=3 in the parabolic equation . This gives,

H=3^2=9\ ft

So, the height of top of tank is, y(3)=H=9\ ft

Now, 5 ft above 'H' means H+5=9+5=14

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

\Delta y=(14-y) ft

Now, area of cross section of the tank is given as:

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Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, y=x^2

So, x=\sqrt y

Therefore, radius, r=\sqrt y

Now, area of cross section is, A(y)=\pi (\sqrt y)^2

Work done in pumping the contents to 5 feet above is given as:

W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy

Plug in all the values. This gives,

W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}

7 0
3 years ago
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