Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Using the Pythagorean theorem:
WY =√(5^2 + 12^2)
WY = √(25 +144)
WY = √169
WY = 13 mm
Can you post the scale drawing please so I can help you
Answer: she is thinking the line might go through the dots on the graph
Step-by-step explanation:
Because when you put the line through the dots on the graph it looks more efishiant. Sorry bad spelling.
3x-4y=65
3x=65+4y
x=(65+4y)/3, when y=4
x=(65+4*4)/3
x=(65+16)/3
x=81/3
x=27
