3 years ago

Ginger practices daily for the upcoming

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

5 days...
you add all the dots on the graph after 30 mins

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What is the first error he made in computing the standard deviation?

artcher [175]

B.yuri divided by n instead of n-1

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2 years ago

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Given two points M & N on the coordinate plane, find the slope of MN , and state the slope of the line perpendicular to MN .

telo118 [61]

Answer:

Problem 1) $m = \dfrac{1}{4}$ $slope_{perpendicular} = -4$

Problem 2) $m = \dfrac{1}{3}$ $slope_{perpendicular} = -3$

Step-by-step explanation:

$slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$slope_{perpendicular} = \dfrac{-1}{m}$

Problem 1) M(9,6), N(1,4)

$slope = m = \dfrac{6 - 4}{9 - 1} = \dfrac{2}{8} = \dfrac{1}{4}$

$slope_{perpendicular} = \dfrac{-1}{\frac{1}{4}} = -4$

Problem 2) M(-2,2), N(4,-4)

$slope = m = \dfrac{4 - 2}{4 - (-2)} = \dfrac{2}{6} = \dfrac{1}{3}$

$slope_{perpendicular} = \dfrac{-1}{\frac{1}{3}} = -3$

4 0

3 years ago

Change this radical to an algebraic expression with fractional exponents.

vekshin1

Rational exponents

$a^\frac{m}{n}$

work like this: the numerator is the actual exponent of the base, while the denominator is the index of the root.

In other words, we have

$a^\frac{m}{n}=\sqrt[n]{a^m}$

So, in you case, we have

$\sqrt[5]{x^3}=x^\frac{3}{5}$

Assuming that the question contanis a typo. If you actually mean $5\sqrt{x^3}$ ,

then you can write it as $5x^\frac{1}{3}$

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3 years ago

Which three statements below are true about an acute isosceles triangle?two side measures are the sameall angle measures are les

lubasha [3.4K]

Two side measures are the same
all angle measures less than 90°
two angle measures are the same

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2 years ago

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In order to solve the system of equations {x-3y=2 {2x+y=11 using the elimination method which of the following steps could be us

Ede4ka [16]

x - 3y =2
2x+ y =11 | *3

x - 3y = 2
6x +3y=33
--------------
7x =35
x=35:7
x=5

x-3y=2
5-3y=2
3y=5-2
3y=3
y=1

4 0

3 years ago