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dedylja [7]
3 years ago
9

Giving 30 points to whoever helps me.Fasttttt and no wrong answers.

Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0
The answer is y = -3x + 10.
The rest is not linear since the rest is not in the form of y = mx +b (a type equation for a line).

Have an awesome day! :)
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Sergio runs 2 1/4 miles in 30 minutes. Write the ratio in fractional form and determine Sergio's speed in miles per hour.
klasskru [66]
\dfrac{ 2\dfrac{1}{4} }{ \dfrac{30}{60} } \\ \\ = \dfrac{9}{4} \div \dfrac{30}{60} \\ \\ = \dfrac{9}{4} \times \frac{60}{30} \\ \\ = 4.5

4.5 miles per hour.

Hope this helps. - M
5 0
3 years ago
Find p if 45 :72=72 40:p​
leonid [27]
Here

45 :72 = 40:p
Or 45/72=40/p
Or 45p = 72*40

Or p = 2880/45

Or p= 64

Thank you
Ayanas
4 0
3 years ago
Condense the logarithm. ylogg - zlogr
Veronika [31]
The logarithm theory is ylogg -zoografías
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3 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
If a jogger runs 2 miles and burns 185 calories, how many calories would he burn
ad-work [718]
Answer:277.5
Explanation: If 185 calories=2 miles then 1 mile=92.5 calories. 185+92.5=277.5
5 0
3 years ago
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