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3 years ago

Giving 30 points to whoever helps me.Fasttttt and no wrong answers.

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

The answer is y = -3x + 10.
The rest is not linear since the rest is not in the form of y = mx +b (a type equation for a line).

Have an awesome day! :)

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Please help me

kirza4 [7]

This is a hexagonal prism: Volume = Area of Base (hexagon) x Height:
There are 6 equal equilateral triangles in a hexagone.
The apothem (or altitude of each triangle) = side x (√3)/2 =12(√3)/2 = 6√3
Area of ONE equilateral triangle = (side x altitude)/2:
Area of ONE equilateral triangle = (12 x 6√3)/2 = 36√3 ft²
Area of the SIX equilateral triangles = 36√3 x 6 = 216√3 ft²
VOLUME = BASE X HEIGHT = 216√3 x 15 = 3240√3 ft³

OR VOLUME = 5612 ft³

6 0

3 years ago

Help! please answer ASAP!

ValentinkaMS [17]

The answer would be 7,6,5,4,3,2,1 inches tall in the chronological order

5 0

3 years ago

Read 2 more answers

Convert 5 square root of a into exponential form?

stich3 [128]

Answer:

The answer is: " $5a^\frac{1}{2}$ " .

_____________________________________________

Step-by-step explanation:

______________________________________________

We are asked to convert "5 square root of a" ; into "exponential form".

Note that "5 square root of a" ;

or; " 5 root a " ;

means: " 5 times the {square root of the variable, "a" };

or : " 5 multiplied by the {square root of the variable, "a" }.

_______________________________________________

This can be written as: " $5\sqrt{a}$ " .

_______________________________________________

Note the following property of exponents:

$\sqrt[n]{a^m} = (\sqrt[n]{a})^m = a^m^n$ .

_____________________________________________

So; to write: " √a " ; as an exponent :

______________________________________________

Note:

" $\sqrt{a} = \sqrt[2]{a} = \sqrt[2]{a^1} = (\sqrt[2]{a})^1 = a^\frac{1}{2}$ " .

_______________________________________________

So:

" $\sqrt{a} = a^\frac{1}{2}$ " ;

_______________________________________________

And:

________________________________________________

" $5\sqrt{a} = 5a^\frac{1}{2}$ " .

________________________________________________

→ The answer is: " $5a^\frac{1}{2}$ " .

________________________________________________

Hope this helps!

Best wishes in your academic endeavors

— and within the "Brainly" community!

________________________________________________

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5Csqrt%7B200%7D%5Ctimes%20%5Csqrt%7B200%7D%20%7D" id="TexFormula1" title="

Darya [45]

Answer:

$\sf \longmapsto200$

Step-by-step explanation:

$\sf \longmapsto\sqrt{200}\times \sqrt{200}$

$\sf \longmapsto \sqrt{200}$

$\sf \longmapsto200$

3 0

3 years ago

Read 2 more answers

The sum of three consecutive integers is 114. what are the three integers?

RSB [31]

Answer: 37, 38, and 39

Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.

3 consecutive integers can be represented as followed.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

Since the sum of our 3 consecutive integers is 114, we can set up an equation to represent this.

X + X + 1 + X + 2 = 114

We can simplify on the left side by combining the X's and the numbers.

3x + 3 = 114

-3 -3 ← subtract 3 from both sides of the equation

3x = 111

÷3 ÷3 ← divide both sides of the equation by 3

X = 37

X ⇒ first integer = 37

X + 1 ⇒ second integer = 38

X + 2 ⇒ third integer = 39

Therefore, our 3 consecutive integers are 37, 38, and 39.

5 0

3 years ago

Read 2 more answers