All categories

3 years ago

Please help!! Will mark brainliest!!

Mathematics

1 answer:

Korolek [52]3 years ago

3 0

I’m so sorry if I did this math wrong. But I’m 99.9% sure I did it right.

1-56
2-42
3-82
4-56
5-45
6-82
7-98
8-82
9-98
10-82
11-98
12-82
13-98
14-82

You might be interested in

3×4×100±67≤65║556∪120D⊥p=13⇆87∞44f1······ HELP PLEASEE WHAT IS THIS????

kkurt [141]

Answer: That is most likely an unsolvable question.

Step-by-step explanation: PEMDAS

3×4×100±67≤65 Doesn’t work.

3x4= 12 ~ 12x100=1200 ~ 1200+67=1267 ~ 1267<65

556∪120D⊥p=13⇆87∞44f1······ Also clearly isn’t a math question

I am not sure if this helps. But I really did look into it and found nothing. I am So sorry to disappoint.

8 0

2 years ago

Eric plays basketball and volleyball for a total of 95 minutes every day. He plays basketball for 25 minutes longer than he play

ioda

Answer:

Part A:

x+y= 95

x = y+25

Part B : 35 minutes

Part C : No

Step-by-step explanation:

Part A :

Eric plays basketball and volleyball for a total of 95 minutes every day

x+y= 95

Where:

x =the number of minutes Eric plays basketball

y= the number of minutes he plays volleyball

He plays basketball for 25 minutes longer than he plays volleyball.

x = y+25

System:

x+y= 95

x = y+25

Part B:

Replacing x=y+25 on the first equation:

(y+25) + y =95

Solving for Y

y+25+y =95

25+2y=95

2y=95-25

2y=70

y = 70/2

y = 35 minutes

Part C : No

if x = 35

x+y= 95

35+y =95

y= 95-35

y = 60 minutes

Replacing y=60 on the other equation:

x = y+25

35 = 60+25

35 ≠85

5 0

3 years ago

4(1-x)+2x=-3(x+1 solve for x

ipn [44]

Answer:

Step-by-step explanation:

6 0

3 years ago

If 5 bags cost 255.35 how much would 2 bags cost

rewona [7]

$255.35 \div 5 = 51.07$

$51.07 \times 2 = 102.14$

8 0

3 years ago

Read 2 more answers

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Solution:

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago