The positive solution to the quadratic equation
is x = 1.39
<h3><u>Solution:</u></h3>
Given quadratic equation is 
<em><u>The general quadratic equation is of form:</u></em>

Now comparing the general equation with the given equation we get
a = 2 , b = 3 and c = -8
<em><u>The formula to determine roots of the quadratic equation is:</u></em>

On plugging in vlaues, we get


On solving we get,


x = 1.39 OR x = -2.89
Hence , the positive solution to the quadratic equation is x = 1.39
M% of p% of n
m/100 · p/100 · n.
G(x)=4x^2-16
To shift to the right we have to subtract from the value of x, in this case by 5 units...
h(x)=4(x-5)^2-16
h(x)=4(x^2-10x+25)-16
h(x)=4x^2-40x+100-16
h(x)=4x^2-40x+84
Now to shift the function downwards by 2 units we must subtract the constant 2 from h(x)
h(x)=4x^2-40x+84-2
h(x)=4x^2-40x+82
Answer:
f^−1(x)=√x+36, −√x+36
Hope this helps! (and I'm sorry if it doesn't)