Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.
<h3>How to find the p-value of a test?</h3>
It depends on the test statistic z, as follows.
- For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.
- For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.
- For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.
In all cases, a higher test statistic leads to a lower p-value, and vice-versa.
<h3>What is the equation for the test statistic?</h3>
The equation is given by:

The parameters are:
is the sample mean.
is the tested value.
- s is the standard deviation.
From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease, and the p-value would increase.
You can learn more about p-values at brainly.com/question/26454209
1000*200=200000
This will be your answer
thanks
Answer:
<em>AB = 5√2</em>
<em>AC = √145</em>
<em>BC = √65</em>
Step-by-step explanation:
Using the formula for calculating the distance between two points
D = √(x2-x1)²+(y2-y1)²
For AB A(-3,6),B(2,1),
AB = √(2+3)²+(1-6)²
AB = √(5)²+(-5)²
AB = √25+25
AB = √50
<em>AB = 5√2</em>
For AC A(-3,6) and C(9,5)
AC = √(9+3)²+(5-6)²
AC = √(12)²+(-1)²
AC = √144+1
<em>AC = √145</em>
For BC B(2,1), and C(9,5)
BC = √(9-2)²+(5-1)²
BC = √(7)²+(4)²
BC = √49+16
<em>BC = √65</em>
<em></em>
<em>Since All the sides are difference, hence triangle ABC is a scalene triangle</em>
The unit rate of 32 is 12
43
= 40+ 3
= 4 tens+ 3 ones.
Another way to describe 43 is 4 tens and 3 ones~