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Masja [62]
3 years ago
7

Charlie solved an equation, as shown below:

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0
Part A:  Charlie's answer is incorrect
In step 2 of Charlie's answer he subtracted 5 from each side.  Since 5x is multiplication, he must DIVIDE each side by 5 to get x by itself.  The problem should have worked out like this...

Step 1:  5x = 30
Step 2:  x = 30/5
Step 3:  x = 6

Part B:  There is only 1 solution for this problem.
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Find the quotient. 64 ÷ 32 =
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Answer:

64÷32=2.

Step-by-step explanation:

if you add 32+32 it's 64, so that means 32x2=64 and yeahhh

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3 years ago
-5f-2+8-3k use f=7 and k=8
yaroslaw [1]
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3 years ago
a pet store buys bags of dog food for 30.00 dollars per bag and sells them for 54.00 dollars per bag. What is the percent markup
Alenkinab [10]

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80%

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7 0
3 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
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