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uysha [10]
3 years ago
10

If

la"> = 65° and j = 11 mm, what is the value of h to the nearest tenth of a millimeter?
A. 4.7 mm
B. 12.1 mm
C. 5.1 mm
D. 8.6 mm

Mathematics
1 answer:
larisa [96]3 years ago
6 0

Answer:

C. 5.1 mm

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan alpha = opposite/ adjacent

tan alpha = j/h

tan 65 = 11/h

Multiply both sides by h

h tan 65 = 11/h *h

h tan 65 = 11

Divide each side by tan 65

h tan 65 / tan 65 = 11 / tan 65

h = 11 / tan 65

h =5.12938424

To the nearest tenth

h = 5.1

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Select the common ratio and the 4th term of the geometric series: 9, -6,4...
Blababa [14]

The given geometric sequence has the common ratio, <u>r = -2/3</u>, and the value of the 4th term, <u>a₄ = -8/3</u>.

A geometric sequence is a special series where every term is the product of the previous term and a common ratio.

The first term of a geometric sequence is represented as a, the common ratio as r, and the n-th term as aₙ, which is calculated as, aₙ = a.rⁿ⁻¹.

In the question, we are asked to find the common ratio and the 4th term of the geometric sequence, 9, -6, 4, ........

The first term of the sequence, a = 9.

The second term of the sequence, a₂ = -6.

By the formula of the n-th term, aₙ = a.rⁿ⁻¹, we can show that:

a₂ = a.r²⁻¹.

Substituting the values, we get:

-6 = 9(r²⁻¹),

or, r²⁻¹ = -6/9,

or, r = -2/3.

Thus, the common ratio of the given geometric sequence is <u>-2/3</u>.

The 4th term can be calculated using the formula of the n-th term, aₙ = a.rⁿ⁻¹ as:

a₄ = a.r⁴⁻¹ = a.r³.

Substituting the values, we get:

a₄ = 9(-2/3)³,

or, a₄ = 9.(-8/27),

or, a₄ = -8/3.

Thus, the 4th term of the given geometric sequence is <u>-8/3</u>.

Learn more about a geometric sequence at

brainly.com/question/24643676

#SPJ1

3 0
2 years ago
PLEASE HELP!!!! Complete the frequency table using the ages above and use the frequency table to make a graph
xxTIMURxx [149]
50-54= 2
55-59= 4
60-64= 3
65-69= 3

I hope this helps But what I did was I counted how many numbers were in between each of the two numbers.
7 0
4 years ago
Read 2 more answers
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