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sergeinik [125]
3 years ago
11

Can someone explain how to do this? thank you!

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0
The answer will be <span>Negative

Write sin(</span>\frac{5 \pi }{4}) as sin(\pi+\frac{ \pi } {4}<span>)

Using the summation identity will be:
</span>=sin(\pi)+cos(\pi)sin(\frac{ \pi }{4}<span>)
</span><span>
By following the trivial identity, you should get:
=</span>0*\frac{ \sqrt{2}}{2}+(-1) \frac{\sqrt 2} {2}

<span>Remove the parentheses on -1, then multiply</span>
=0*\frac{ \sqrt 2} {2}-1* \frac{ \sqrt 2} {2}

You should get:
- \frac{ \sqrt 2} {2}
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Answer:

Domain: [-2, 2]

Range: [-3, 3]

Step-by-step explanation:

Domain (x) is the left and right. Range (y) is the up and down.

It's a bracket if it is included, meaning, there is no gap or hole.

If it weren't included, it'd be a parentheses instead "( )". For example, if there was an open circle.

It would go to -infinty or +infinity if it were to go on forever, and that would be in parentheses.

EX: (-∞,∞) or (-∞, 8]

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3 years ago
What is an equation of the line that passes through the point (3,-1) and is parallel to the line 5x+3y=6
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Answer:

y=-\frac{5}{3} x+4

Step-by-step explanation:

Since the line we are trying to study is parallel to the one given by the standard equation 5x + 3y = 6, it needs to have the same slope as this given line has. Let's write then this equation in slope-intercept so we can find what the slope is :

5x+3y=6\\3y=-5x+6\\y=-\frac{5}{3} x+\frac{6}{3} \\y=-\frac{5}{3} x+2

Then the slope of our line must also be "-5/3" in order to be parallel to the given line.

Now, since we also know a point (3, -1) through which the new line should go, we use the point-slope form of a line:

y-y_0=m(x-x_0)\\y-(-1)=-\frac{5}{3} (x-3)\\y+1=-\frac{5}{3} x+5\\y=-\frac{5}{3} x+4

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3 years ago
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