A set of final examination grades in an introductory statistics course is normally distributed, with a mean of 77 and a standar
1 answer:
Answer:
0.9007 is the probability that a student scored below 86 on this exam.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 77
Standard Deviation, σ = 7
We are given that the distribution of examination grades is a bell shaped distribution that is a normal distribution.
Formula:
a) P(student scored below 86)
P(x < 86)
Calculation the value from standard normal z table, we have,
0.9007 is the probability that a student scored below 86 on this exam.
You might be interested in
Answer:
The first step is sort the values on increasing order and we got:
18, 18, 19, 19, 19, 20, 22, 23. 25, 26, 31
And in order to find the first quartile we can separate the first 5 lowest values from the largest 5 values. And for this case we focus on these values:
18, 18, 19, 19, 19
And if we find the median of the last 5 values we can find the first quartile and we got:
The best answer would be:
19
Step-by-step explanation:
For this problem we have the following dataset:
18, 26, 19, 25, 19, 23, 31, 22, 19, 18, 20
The first step is sort the values on increasing order and we got:
18, 18, 19, 19, 19, 20, 22, 23. 25, 26, 31
And in order to find the first quartile we can separate the first 5 lowest values from the largest 5 values. And for this case we focus on these values:
18, 18, 19, 19, 19
And if we find the median of the last 5 values we can find the first quartile and we got:
The best answer would be:
19