(6^2)^4 simplify expression

Can someone help me please and I need the work to please

ehidna [41]

Answer:

46

Step-by-step explanation:

10 + 6^2

10 + 6 x 6

10 + 36

46

6 0

3 years ago

Solve by the quadratic formula x^2 = 6x-4

tresset_1 [31]

Answer:

x=3+√5 or x=3−√5

Step-by-step explanation:

6 0

3 years ago

A point of sale transaction occurs when a debit card is used to purchase items at a grocery store. please select the best answer

Romashka-Z-Leto [24]

It is a true statement that; "A point of sale transaction occurs when a debit card is used to purchase items at a grocery store."

<h3>What is a debit card?</h3>

A debit card is a small card that contains a chip which a bank issues to its customers to enable them to perform cashless transactions outside the banking hall.

It is a true statement that; "A point of sale transaction occurs when a debit card is used to purchase items at a grocery store."

Learn more about debit card:brainly.com/question/27350251

#SPJ4

6 0

2 years ago

A consumer products company found that 42% of successful products also received favorable results from test market research, w

blagie [28]

Answer:

(1) The probability of a successful product given the product is favorable is 0.7778.

(2) The probability of a successful product given the product is unfavorable is 0.2391.

(3) The probability of a unsuccessful product given the product is favorable is 0.2222.

(4) The probability of a unsuccessful product given the product is favorable is 0.7609.

Step-by-step explanation:

Denote the events as follows:

<em>S</em> = a product is successful.

<em>F</em> = a product is favorable.

The information provided is:

$P(S\cap F)=0.42\\P(S\cap F^{c})=0.11\\P(S^{c}\cap F)=0.12\\P(S^{c}\cap F^{c})=0.35\\$

The law of total probability states that:

$P(A)=P(A\cap B)+P(A\cap B^{c})$

Use the law of total probability to compute the probability of a favorable product as follows:

$P(F)=P(S\cap F)+P(S^{c}\cap F)\\=0.42+0.12\\=0.54$

The probability of a favorable product is 0.54.

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

(1)

Compute the value of P (S|F) as follows:

$P(S|F)=\frac{P(S\cap F)}{P(F)}=\frac{0.42}{0.54}=0.7778$

Thus, the probability of a successful product given the product is favorable is 0.7778.

(2)

Compute the value of $P(S|F^{c})$ as follows:

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}=\frac{0.11}{(1-0.54)}=0.2391$

Thus, the probability of a successful product given the product is unfavorable is 0.2391.

(3)

Compute the value of $P (S^{c}|F)$ as follows:

$P (S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F)}=\frac{0.12}{0.54}=0.2222$

Thus, the probability of a unsuccessful product given the product is favorable is 0.2222.

(4)

Compute the value of $P (S^{c}|F^{c})$ as follows:

$P (S^{c}|F)=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}=\frac{0.35}{(1-0.54)}=0.7609$

Thus, the probability of a unsuccessful product given the product is favorable is 0.7609.

8 0

3 years ago

Partcial products 73÷584

Crank

Seventy-three divided by five-hundred-eighty-four equals 0.125

4 0

4 years ago