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Alex Ar [27]
4 years ago
13

A circuit contains two capacitors rated at 0.02 microfrads and 0.05 microfrads connected in series the circuits Source voltage i

s 30vac what is the circuits total capacity
Mathematics
1 answer:
Neporo4naja [7]4 years ago
8 0

Answer:

  about 0.0143 microfarads

Step-by-step explanation:

The effective capacitance of capacitors in series is the reciprocal of the sum of their reciprocals:

  1/(1/0.02 +1/0.05) = 1/(50+20) = 1/70 ≈ 0.0143 . . . microfarads

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snow_lady [41]
The answer is C.0.2
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3 0
3 years ago
a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m
lesya [120]

Answer:

62.5 \:in^2

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism=x^2l

Since l=5 Inches

5x^2=31.25\\x^2=6.25\\x=2.5\: Inches

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area=2(x^2+xl+xl)=2(x^2+2xl)

=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2

Therefore, 62.5 \:in^2 of cardboard is needed,

4 0
3 years ago
What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


8 0
3 years ago
Read 2 more answers
Find the magnitude of −1−5i
ladessa [460]

The magnitude of -1-5i is √26.

<h3>What is the magnitude of -1-5i ?</h3>

Given the complex expression; -1 - 5i

To find the magnitude, we use the formula;

| a+bi | = √[ a² + b² ]

  • a = -1
  • b = -5

| a+bi | = √[ a² + b² ]

| -1-5i | = √[ (-1)² + (-5)² ]

| -1-5i | = √[ 1 + 25 ]

| -1-5i | = √26

Therefore, the magnitude of -1-5i is √26.

Learn more about magnitudes here: brainly.com/question/18152189

#SPJ1

8 0
2 years ago
I will NAME YOU THE BRAINIEST
Dmitry_Shevchenko [17]

Answer:

see below

Step-by-step explanation:

Since the quadrilateral is inscribed in the circle, the opposite angles add to 180.

<V+ <B = 180

74+ <B = 180

Subtract 74 from each side

74-74+ <B = 180-74

<B = 106

We now need to find arc AB

Arc AC is 2* <V = 2*74 =154

We know arc AC = arc AB + arc BC

                 154 = arc AB + 86

Subtract 86 from each side

                154-86 = arc AB + 86 -86

                  68 = arc AB

8 0
3 years ago
Read 2 more answers
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