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3 years ago

Can someone help me ?????????

Mathematics

1 answer:

attashe74 [19]3 years ago

4 0

Answer:

The answer to your question is A.

Step-by-step explanation:

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Divide (x^3+2x^2-x-2) by (x-1)

Ymorist [56]

$\frac{x^3+2x^2-x-2}{(x-1)} =x^2+3x+2 \\ \\ x^3+2x^2-x-2= \\= x^2(x+2)-(x+2) \\ =(x+2)(x^2-1)=(x+2)(x-1)(x+1) \\ \\ \frac{x^3+2x^2-x-2}{(x-1)} = \frac{(x+2)(x-1)(x+1)}{x-1} =(x+2)(x+1)=x^2+3x+2$

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3 years ago

What is the length of line segment ab

Leokris [45]

The length of the line segment here is 13.

Distance Formula:
√((x₂ - x₁)² + (y₂ - y₁))
√((5 - 0)² + (0 - 12)²) = 13

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2 years ago

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What are two decimals close two 6.3

WITCHER [35]

Answer:

6.2 and 6.4

Step-by-step explanation:

I am right please like

5 0

3 years ago

find the surface area of rectangular prison with a width,length and height of 3m and 15m respectively

Shalnov [3]

Answer:

A=45m^2

Step-by-step explanation:

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4 0

3 years ago

Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

iren2701 [21]

Answer:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

8 0

3 years ago