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Rudiy27
3 years ago
8

2 ones equal how many tenths

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0
2 ones are equal to 20 tenths
Aleksandr-060686 [28]3 years ago
5 0
2 ones are equal to 0 tens
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Hue is arranging chairs. She can form 2 rows of a given length with 2 chairs left over, or 6 rows of that same length if she get
Nady [450]
There are 7 chairs in each row length.
Step-by-step explanation:
Let number of chairs in 1 row be 'x'.
Let total number of chairs be 'y'.
Given:
Hue can form 6 rows of a given length with 3 chairs left over.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.

Also Given:
Hue can form 8 rows of that same length if she gets 11 more chairs.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 8 minus number of chairs which is required more which is 11.
Framing in equation form we get.

From equation 1 and equation 2 we can say that L.H.S is same.
So according to law of transitivity we get;

Combining like terms we get;

Using Subtraction and Addition property we get;

Now Using Division Property we will divide both side by 2.

Hence there are 7 chairs in each row length.
8 0
3 years ago
Find the factors that multiply to give you -42 and add to give you -1.
Schach [20]
-7 and positive 6. if you multiply a negative by a positive it will always be a negative.
3 0
3 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
30 ft
LekaFEV [45]

Answer:30+15

Step-by-step explanation:

4 0
3 years ago
Solve for the indicated variable <br>k = a - y; y​
Varvara68 [4.7K]

(This user has been deleted.)

8 0
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