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zimovet [89]
3 years ago
15

What is the solution to the linear equation d-10-2d+7=8+d-10-3d

Mathematics
2 answers:
bija089 [108]3 years ago
8 0
D-10-2d+7 = 8 + d- 10 -3d
d-2d-10+7 = 8-10 +d -3d
-d-3=-2-2d
-d+2d=3-2
d=1

Final answer: C. d=1
solmaris [256]3 years ago
5 0
D-10-2d+7 = 8 + d- 10 -3d

=> d -2d -10+7 = 8 -10 +d - 3d
=>-d - 3 = -2 -2d
=>-d+2d = -2 +3
<span>=> d = 1 ..

Hope it helps !!!</span>
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4/x - 3/y = 1 ; 6/x + 15/y = 8 solve this equation​
Soloha48 [4]

Answer:

x=2

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Solution:

First we find common denominators. It is "xy". Then we multiply numerators by common denominator. We get followings:

(4y-3x)/xy=1; (6y+15x)/xy=8

Then

4y-3x=xy;

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Multiply first equasion by 5

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Now we add two equasions to get one

20y-15x=5xy

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We get

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4 0
3 years ago
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Ostrovityanka [42]

Answer:

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Step-by-step explanation:

Given points:

(0,-2) and (-8,-8)

To find the distance between the two points.

Solution:

Applying distance formula to find the distance between the points.

For points (x_1,y_1) and (x_2,y_2) the distance is given as:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Plugging in the given points in the formula.

d=\sqrt{(-8-0)^2+(-8-(-2))^2}

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d=\sqrt{(-8)^2+(-6)^2}

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3 years ago
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It can depicted that for t= 0 secs the ball is at 5 feet and so on .

Therefore the range is given by numbers from 5 to 12.5.

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