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3 years ago

Y=9x+7,y=3x-11 i need to solve theeqayions by substition and show the work

Mathematics

1 answer:

djyliett [7]3 years ago

4 0

Times the second equation by 2 to get y=9x-33 and then subtract

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I really need help ................................................

Helga [31]

When is this homework due?

7 0

2 years ago

Multiply.<br>(2x-5) (3x-7)

Naya [18.7K]

Answer:

6x^2 -29 +35.

Step-by-step explanation:

use the FOIL method(First, Outer,Inner, and Last.)

2x x 3x=6x^2.

2x x -7=-14x.

-5 x 3x =-15x.

-5 x -7=35.

= 6x^2 -14x -15x+35

6x^2 -29x +35.

4 0

2 years ago

Does the point (-9,-4) satisfy the equation y = x + 5?

ozzi

Answer:

Yes it satisfies the equation

Step-by-step explanation:

Let, P(x,y) = (-9,-4)

Then, x = -9

y = -4

if we use this value in the equation, we will get L.S = R.S ;(-4 = -9 + 5)

So, the point satisfies the equation

Hope you have understood this

Pls mark my answer as the brainliest

5 0

2 years ago

The radius of a circle is 10 cm. Find its circumference in terms of pi

sergejj [24]

Answer:

20 pi is the correct answer

5 0

2 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

2 years ago