Answer:
Option C. is the correct option.
Step-by-step explanation:
The given line in the graph passes through two points (0, 3) and (3, 7).
We have to find the equation of the line.
Since y = mx + c is the standard equation of a line
where m = slope of the line
c = y - intercept
Slope of a line m = 
Now we put the values of x and y to find the slope of this line.
m = 
Since (0, 3) passes through the line
3 = 0 + c
c = 3
Equation of the line will be

Option C. is the answer.
Answer:
(x, y) = (-10, 5)
Step-by-step explanation:
This one can be a little tricky because the variables in the equations are not in the same order. It might help to rewrite the system as ...
Multiplying the first equation by 3 and subtracting 2 times the second equation can eliminate the y-variable:
3(5x +6y) -2(2x +9y) = 3(-20) -2(25)
11x = -110 . . . . . . simplify
x = -10 . . . . . . . . divide by 11
5(-10) +6y = -20 . . . substitute for x in the first equation
6y = 30 . . . . . . . . add 50
y = 5 . . . . . . . . . . divide by 6
The solution is (x, y) = (-10, 5).
Answer: In order to find what the coordinates of B are is by trying to know how we got to (-2,0) of line AB. You have to subtract 3 from A coordinate x which is 1,it will give you -2, and you have to subtract 1 from A coordinate y which is 1,it will give you 0.
Find the closest whole number estimate for 3.8 and 6.1
The estimate for both numbers are, 4 and 6.
3.8 is rounded up to the nearest whole number, while 6.1 is rounded down to 6because the 1 after the decimal is an insignificant number (its less than 5)
Answer: F = 25.1 kHz
Step-by-step explanation:
Time (period) = 250 × 10^-6 s
Let's first calculate the folding frequency. Given by
NF (rad s-1) = π/Δt
where NF = Nyquist frequency
t = time increment between observations.
The original signal must be filtered by analog or physical methods to remove all frequencies higher than the Nyquist frequency before the signal is sampled or digitized.
F = 3.143/0.00025
F = 12566.37Hz
minimum sampling rate = 2F
2 × 12566.37 = 25132.74Hz
minimum sampling rate = 25.1 KHz