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Lapatulllka [165]
3 years ago
8

Suppose M is the midpoint of line FG.

Mathematics
1 answer:
alukav5142 [94]3 years ago
6 0
A)\\|FM|=5y+13;\ |MG|=5-3y\\\\|FG|=|FM|+|MG|\\\\|FG|=(5y+13)+(5-3y)=2y+18\\\\B)\\|FM|=8a+1;\ |FG|=42\\\\|FG|=2|FM|\\\\2(8a+1)=42\\16a+2=42\ \ \ \ \ |subtract\ 2\  from\ both\ sides\\16=40\ \ \ \ \ |divide\ both\ sides\ by\ 16\\a=\frac{40}{16}\\a=\frac{5}{2}\\a=2.5

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