We have that
x²<span>-6x+7=0
</span>Group terms that contain the same variable
(x²-6x)+7=0
Complete the square Remember to balance the equation
(x²-6x+9-9)+7=0
Rewrite as perfect squares
(x-3)²+7-9=0
(x-3)²-2=0
(x-3)²=2
(x-3)=(+/-)√2
x=(+/-)√2+3
the solutions are
x=√2+3
x=-√2+3
Answer:
The equation of a parallel line in point-slope form would be y - 3 = -8(x + 3)
Step-by-step explanation:
To find this, we must first note that the original slope is -8. Parallel lines have the same slope, so we know that the new line will also have the slope of -8.
Given this information, we can use the point and slope and put them into the base form of point-slope form.
y - y1 = m(x - x1)
y - 3 = -8(x - -3)
y - 3 = -8(x + 3)
Answer:
1) 2m + 3m2 - 4m=7
7) 3m2 – 2m + 4m= 11
8) 20 + 109 + 39 - 4= 164
3) 2m + 4m - 3m2= -3
9) 4xy + x + 2xy= 0
4) 2y + 14x - 7x + 9y= 18
10) 6m2 - 6m - 9m2= -51
Step-by-step explanation:
Answer:
6.41
Step-by-step explanation:
if u subtract 6.38 from 6.41 you have .03 left over.
Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be 
Let weight of each okapi be 
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em>
</em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em>
</em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:
Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:
Each okapi weigh 290 kg
