In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS
<h3>What are
congruent triangles?</h3>
Two triangles are said to be congruent if they have the same shape, all their corresponding angles as well as sides must also be congruent to each other.
Two triangles are congruent using the side - angle - side congruency if two sides and an included angle of one triangle is congruent to that of another triangle.
In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS
Find out more on congruent triangle at: brainly.com/question/1675117
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(x-8) ^ 2 = 121
(x-8) = + / - root (121)
x = 8 +/- root (121)
The solutions are:
x1 = 8 + root (121)
x2 = 8 - root (121)
2a ^ 2 = 8a-6
2a ^ 2-8a + 6 = 0
a ^ 2-4a + 3 = 0
(a-1) (a-3) = 0
The solutions are:
a1 = 1
a2 = 3
x ^ 2 + 12x + 36 = 4
x ^ 2 + 12x + 36-4 = 0
x ^ 2 + 12x + 32 = 0
(x + 4) (x + 8) = 0
The solutions are:
x1 = -8
x2 = -4
x ^ 2-x + 30 = 0
x = (- b +/- root (b ^ 2 - 4 * a * c)) / 2 * a
x = (- (- 1) +/- root ((- 1) ^ 2 - 4 * (1) * (30))) / 2 * (1)
x = (1 +/- root (1 - 120))) / 2
x = (1 +/- root (-119))) / 2
x = (1 +/- root (119) * i)) / 2
The solutions are:
x1 = (1 + root (119) * i)) / 2
x2 = (1 - root (119) * i)) / 2
Answer:
17.6 minutes
Step-by-step explanation:
83 divided by 3.
Exact Form: 83/3
Decimal Form: 27.66666666. . .
Mixed Number Form: 27 2/3
To find the height of the TV you first need to realize that the question is giving you dimensions for a triangle.
Every triangle has a hypotenuse and two sides. To find the hypotenuse you square both sides, add them, and then square root. So to find one of the sides you get the hypotenuse, square it, and subtract the square length of the given side.
The equation is 25^2-20^2.
Which if simplified is 625-400, the then solution is going to be 225.
You next will square root 225, 225^(1/2). Which your answer should be 15 inches for the missing side length.
