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Nadusha1986 [10]
3 years ago
8

The exponential population growth equation can be used for

Mathematics
1 answer:
Margaret [11]3 years ago
7 0
Gettng answers obviosly please give me more points i neeedddd them.

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Determine the sample size needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and
WINSTONCH [101]

Answer:

n=170

Step-by-step explanation:

1) Notation and definitions

n random sample taken (variable of interest)

\hat p=0.65 estimated proportion.

p true population

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=\pm 1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.06 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.65(1-0.65)}{(\frac{0.06}{1.64})^2}=169.968  

And rounded up we have that n=170

6 0
4 years ago
After dans holiday. Dan has 50 new email messages in his inbox . 13 of them are attachements. what proportion of the email messa
dimulka [17.4K]

Answer:

26%

Step-by-step explanation:

Given that Dan has 59 new email messages and 13 have attachment then the proportion that have attachments may be expressed as a ratio of the number with attachments to the total number of emails.

Hence proportion of the email messages have attachments as a percentage

= 13/50 * 100%

= 26%

This means that 26% of the emails received have attachments

6 0
3 years ago
PLEASE HELP ME!!!! FOR 11 POINTS!!
Alex_Xolod [135]

Answer:

1. .900+.020+.008, 2. .700+.030+.001, 3. 4.5, 4.56, 4.565656, 4.6

Step-by-step explanation:

8 0
3 years ago
Evaluate the algebraic expression below for the given value.
MrRa [10]

hi

i think this will help you

4 0
3 years ago
Jen uses 8.6 gallons of gasoline to drive 164.7 miles. Which is the best estimate for thenumber of miles per gallon of gasoline
zimovet [89]

Answer:

C

Step-by-step explanation:

164.7/8.6 = 19.15

about 20 miles per gallon

4 0
3 years ago
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