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2 years ago

Nyasia had 16 M&M’s on her desk. She had 2 groups of M&M’s

Mathematics

1 answer:

Maksim231197 [3]2 years ago

3 0

Answer:

Step-by-step explanation:

total mnm 16

group 1= 4 mnm

group 2= x mnm

group 3= x mnm

group 1+ group 2+ group 3= 16

4+ x+x=16

2x= 16-4

x= 14/2

x=7

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Different shapes are drawn on cards and then the cards are placed in a bag. The number of cards for each shape is shown in the t

Goshia [24]

70% or 91/130.

There are 91 circle cards and 130 total.

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3 years ago

Read 2 more answers

1. Escribe como potencia los siguientes productos y luego resuelve como se indica en el ejemplo. a) 6.6.6 = 6 3 = 216 f) 11.11=

alexandr402 [8]

Answer:

(Véase la explicación para mayores detalles/See the explanation for further details)

Step-by-step explanation:

a) Tres al cubo (Three to cube):

$x = 3 \times 3 \times 3$

$x = 3^{3}$

$x = 27$

b) Seis al cubo (Six to cube):

$x = 6 \times 6 \times 6$

$x = 6^{3}$

$x = 216$

c) Cinco al cuadrado (Five squared):

$x = 5 \times 5$

$x = 5^{2}$

$x = 25$

d) Ocho al cuadrado (Eight squared):

$x = 8 \times 8$

$x = 8^{2}$

$x = 64$

e) Dos a la quinta (Two to five):

$x = 2 \times 2 \times 2 \times 2 \times 2$

$x = 2^{5}$

$x = 32$

f) Diez a la cuarta (Ten to four):

$x = 10\times 10 \times 10 \times 10$

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2 years ago

Please help!!!!!! ASAP!!!

Kitty [74]

Answer:

B. po ang answer sa palagay ko lang po

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2 years ago

Find the cardinality of the set B = { 5, 6, 7, … , 100}

vaieri [72.5K]

The cardinality of the set B is given to be 96.

<h3>What is the cardinality of a set?</h3>

This is the term that is used to refer to the number of elements that a given set can be said to contain.

This is a set that has numbers that ranges from 5 to 100, this tells us that the numbers 1, 2, 3, 4 are excluded from the set.

Hence the total numbers excluded is 4. 100 - 4 = 96

Therefore from 5 to 100, the total 9 and the cardinality of the set B is 96.

Read more on the cardinality of a set here: brainly.com/question/23976339

#SPJ1

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9 months ago

Please help !! Geometry homework. Will mark brainliest answer !

sergeinik [125]

For this case we have:

By trigonometric property we have:

$Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}$

Where:

$Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x$

Substituting:

$Cosine(x)=\frac{12}{13}$

Clearing x we have:

$x =Cosine^{-1}(\frac{12}{13})$

Thus, the equation is: $x =Cosine^{-1}(\frac{12}{13})$

Answer:

$x =Cosine^{-1}(\frac{12}{13})$

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2 years ago