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4 years ago

Write 8.77 as a mixed number, reduced to lowest terms.

1 answer:

8 0

Converting a decimal to a mixed number is very simple when you get the hang of it. Since 8 is before the decimal, that is your number in the mixed number. For the fraction part, it's 77/100. The denominator is 100 because when you count the decimal places, it goes to hundredths. 77/100 is already in simplest form, so your final answer is 8 77/100.

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What is the formula for the following geometric sequence? -5, -10, -20, -40, ... an = -5 · 2n - 1 an = -5 · (-2)n - 1 an = -2 ·

vazorg [7]

$-5 * 2^{n-1}$

8 0

3 years ago

What is the answer to his question

horsena [70]

Answer:

A. 720 per hour

Step-by-step explanation:

1200+ 720 + 720 + 360 =3000

hr 1↑+ hr 2↑ + ↑30 min

8 0

3 years ago

Need help on this question asap please please thank you!

Nutka1998 [239]

Answer:

see explanation

Step-by-step explanation:

The solutions to the systems of equations are at the points of intersection of the 2 graphed functions.

There are 2 points of intersection , so 2 solutions at

(0, - 3 ) and (4, 5 )

There is 1 point of intersection, so 1 solution at

(- 2, 5 )

There are no points of intersection , so no solution

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2 years ago

How are percent transmittance and absorbance related algebraically?

statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:

A ∝ b · c

As Transmittance, $T =\dfrac{P}{P_0}$

% Transmittance, $\%T=100\times T$

Absorbance,

$A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T$

Hence, $A=\log_{10}\times \dfrac{1}{T}$ is the algebraic relation between absorbance and transmittance.

8 0

3 years ago

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bo

Furkat [3]

Answer: B

Step-by-step explanation:

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. Since the machines are identical and running at the same constant rate, it means each of them as the same rate. The rate of each machine can produce would be determined by dividing the combined unit rate by 6. It becomes

270/6 = 45 bottles per minutes

The rate for 10 machines running at the same constant rate would be

10 × 45 = 450 bottles per minutes.

If the 10 machines produce 450 bottles per minutes, then,

In 4 minutes, the 10 machines will produce 4 × 450 = 1800 bottles

4 0

3 years ago