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3 years ago

If your breakfast costs $12 and you are

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

8 0

Answer:

find 9% of 12

12 times 9 divided by 100

108/100

$1.08

12+1.08

Your mean costs $13.08

-Have a nice meal!

Elena-2011 [213]3 years ago

5 0

The answer is $13.08 and here are the steps :)

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18. What is the area of a piece of garden plot 5 yards 2 feet long by 6 yards 1 foot wide? Give your answer in square feet.

34kurt

Answer:

Step-by-step explanation:

1 yard = 3 feet

5yd 2ft = (5)(3)ft + 2ft = 17ft

6yd 1ft = (6)(3)ft + 1ft = 19ft

The formula of an area of a rectangle:

A = wl

w - width

l - length

Substitute w = 19ft and l = 17ft:

A = (19)(17) = 323 ft²

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3 years ago

Only square matrices have multiplicative identities. True or false

Alex

Answer:

true.

Step-by-step explanation:

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3 years ago

(3x^3 + 2x^2 - 2) + (x^2 + 5x - 6)

Alecsey [184]

Answer:

3x^3+3x^2+5x-8

Step-by-step explanation:

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3 years ago

The length of a bridge on a map is 1.5 cm. What is the actual length of the bridge in meters if the map is drawn at a scale of 1

Vitek1552 [10]

Answer:

The actual length of the bridge is 600 meters

Step-by-step explanation:

we know that

The scale on a map is

$\frac{1}{40,000}$

That means

1 unit on a map represent 40,000 units in the actual

1 cm on a map represent 40,000 cm in the actual

Remember that

$1/ m=100/ cm$

$40,000\ cm=40,000/100=400\ m$

we can rewrite the scale as

$\frac{1}{400}\frac{cm}{m}$

using proportion

Find out the actual length of the bridge in meters if the length of a bridge on a map is 1.5 cm.

Let

x ----> the the actual length of the bridge in meters

$\frac{1}{400}\frac{cm}{m}=\frac{1.5}{x}\frac{cm}{m}\\\\x=400(1.5)\\\\x=600\ m$

6 0

3 years ago

Solve the quadratic equation: 3x2 + x - 5 = 0

Yuri [45]

Hey there!

$3x^2 + x -5 = 0$

This equation is in standard form, which is $ax^2+bx+c=0$ .

We are going to solve this with the quadratic equation, so we need to find the values for a, b, and c in the given equation. We can just look at it and identify the variables.

a = 3, b = 1, c = -5

Let's plug these values into the quadratic equation:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-1\pm\sqrt{1^2-4(3)(-5)} }{2(3)}$

Multiply 4(3)(-5) together and multiply 2(3). Square 1.

$x=\frac{-1\pm\sqrt{1+60} }{6}$

Add 1 and 60.

$x=\frac{-1\pm\sqrt{61} }{6}$

This is our answer in exact form. If you need this as an approximate value, let me know and I will do that for you.

Hope this helps!

8 0

3 years ago