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otez555 [7]
3 years ago
6

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if te flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?
Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0
The probability that Jenny gets to choose lunch is  64%  0.64 (rounded) or 0.636.

Work:

Number of roses and carnations divided by the total number of flowers

<span>7/11 = 0.636 = 0.64 (rounded)

once again same answer
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You might be interested in
If the spinner is spun twice, what is the probability that the numbers that are spun don't match?
WITCHER [35]

Answer:

25%

Step-by-step explanation:

There are 4 spots and to get the same you would land on the same 1

Which would be 1/4=25%

Hope this helps!

6 0
4 years ago
Read 2 more answers
Answer this please! It would help me alot. :)
vagabundo [1.1K]

Answer:

Equivalent. 0.4(k+3)=0.4k+1.2

Step-by-step explanation:

x means multiplication. k is the variable.

Hi.

So, you have to distribute the 0.4 into the parenthesis to get rid of them. So, you do 0.4xk, which is just 0.4k, and 0.4x3, which is 1.2. So, you have 0.4k+1.2, which means it is Equivalent.

8 0
1 year ago
Please help. Thank you.
Trava [24]

Answer:

By the Pythagoras theorem, the hypotenuse (c), is equivalent to:

a^2+ b^2= c^2 where a and b are the other two sides of the right angled triangle, hence c= square root (15^2+ 20^2)= 25

4 0
3 years ago
Which statement(s) is (are) correct?
Anna71 [15]

Answer:

<em>statements 3 and 4 are correct.</em>

Step-by-step explanation:

(1)

The probability of choosing cured pasta and bear= probability that the card is king.

Hence, The probability of choosing cured pasta and bear=\dfrac{4}{52}=\dfrac{1}{13}

Probability of choosing baked cucumber and lime mutton=probability that the card is 3.

as there are 4 cards that are '3'.

Hence Probability of choosing baked cucumber and lime mutton=\dfrac{4}{52}=\dfrac{1}{13}

as both the probabilities are equal.

Hence statement 1 is incorrect.

(2)

The probability of choosing gooseberry & passion fruit cheesecake= Probability taht the card is ace.

as there are 4 cards which are ace out of 52 cards.

Hence, The probability of choosing gooseberry & passion fruit cheesecake=\dfrac{4}{52}=\dfrac{1}{13}

probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator=\dfrac{12}{52}=\dfrac{3}{13}

Hence, the probability of choosing gooseberry and passion fruit cheesecake is smaller than the probability of choosing poached fennel & lemon alligator.

Hence statement 2 is false.

(3)

The probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer=\dfrac{13}{52}=\dfrac{1}{4}

the probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator=\dfrac{12}{52}=\dfrac{3}{13}

Hence, The probability of choosing a praline wafer is greater than the probability of choosing poached fennel & lemon alligator.

Hence statement 3 is correct.

(4)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,  

The probability of choosing pressure-cooked mushroom & garlic chicken =\dfrac{26}{52}=\dfrac{1}{2}

probability of choosing an oven-baked apple & lavender calzone =probability that the card is black.

As there are 26 red cards out of 52 cards.

Hence,  probability of choosing an oven-baked apple & lavender calzone=\dfrac{26}{52}=\dfrac{1}{2}

Hence, The probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing an oven-baked apple & lavender calzone are the same.

Hence statement 4 is true.

(5)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,  

The probability of choosing pressure-cooked mushroom & garlic chicken =\dfrac{26}{52}=\dfrac{1}{2}

the probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer=\dfrac{13}{52}=\dfrac{1}{4}

Hence, the probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing a praline wafer are not same.

Hence, statement 5 is not correct.


6 0
4 years ago
Can someone please help me figure this out, thanks!
AURORKA [14]

Answer:

The set of numbers that could not represent the three sides of a right triangle are;

{9, 24, 26}

Step-by-step explanation:

According to Pythagoras's theorem, when the lengths of the three sides of a right triangle includes two legs, 'x', and 'y', and the hypotenuse side 'r', we have;

r² = x² + y²

Where;

r > x, r > y

Therefore, analyzing the options using the relationship between the numbers forming the three sides of a right triangle, we have;

Set 1;

95² = 76² + 57², therefore, set 1 represents the three sides of a right triangle

Set 2;

82² = 80² + 18², therefore, set 2 represents the three sides of a right triangle

Set 3;

26² = 24² + 9², therefore, set 3 could not represent the three sides of a right triangle

Set 4;

39² = 36² + 15², therefore, set 4 represents the three sides of a right triangle

4 0
3 years ago
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