Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

Question

2 years ago

6

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if te flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?

Mathematics

1 answer:

Law Incorporation [45] · Answer 1 · 2022-07-18T19:09:38+03:00

Law Incorporation [45]2 years ago

4 0

The probability that Jenny gets to choose lunch is 64% 0.64 (rounded) or 0.636.

Work:

Number of roses and carnations divided by the total number of flowers

7/11 = 0.636 = 0.64 (rounded)

once again same answer