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7nadin3 [17]
3 years ago
9

A husband and wife celebrate their birthdays on the same day of the month, but in different months. every year, their birthdays

fall on the same day of the week. if the husband's birthday is in March and the wife's birthday is later in the year, find the month of the wife's birthday
Mathematics
2 answers:
irina [24]3 years ago
8 0

Answer:

My B-day is on March!

Step-by-step explanation:

pychu [463]3 years ago
3 0
Husband is in march
wife is after march
we have
b-days are same day
ex march 3 and june 3
also, they fall on the same day of the week
so continuing ex. march 3 wed and june 3 wed

so we just look at the calllendar for days that fall on the same day of the week and have the same nuber and are after march
basically, the easy way to find it is to look at the months and see which months that are after march start on the same day
ex. this year march 1 is on a tuesday
so find other months that start on tuesday
answer is September and December

so the Wife's birthday could be in September or December
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In an arithmetic sequence, the 10th term is 37, and the 21st term is 4. Find the common difference and the first term
Masja [62]

Answer:

Common difference is 3. And the first term is 64.

Step-by-step explanation:

The differnce between 21 and 10 is 11. So there are 11 unknown numbers in between.  And the difference between 37 and 4 is 33. 33/11 is equal to 3. So the pattern is minus three. the first term is 9 terms before 37. 9 times 3 is 27. 37+27 is equal to 64. so the first term is 64

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3 years ago
Answer the following questions step by step with explanations!<br><br>1 × 2 × 3 ÷ 1 × 0 + 6​
pogonyaev

Answer:

6

Step-by-step explanation:

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sesenic [268]

Answer: $189 000

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3 years ago
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belka [17]

Answer:

The answer to your questions is: 25 new teachers

Step-by-step explanation:

Data

# of students = 2000

ratio = 3:80 teachers to students

New teachers = ?

Process

I suggest to use rule of three to solve this problem

                     3 teachers ----------------  80 students

                      x                ----------------  2000 students

                  x = (2000 x 3) / 80 = 75 teachers

               Number of initial teachers = 75

The ratio change to 1:20

                     1 teacher -------------------  20 students

                     x             -------------------   2000 students

                     x = (2000 x 1) / 20

                    x = 100 teachers

Number of new teachers = 100 - 75 = 25

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