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HACTEHA [7]
4 years ago
5

Let u = 14. What is the value of 4u?

Mathematics
2 answers:
Vikki [24]4 years ago
6 0

Answer:

<em>B) 56</em>

Step-by-step explanation:

u = 14

so 4u would be ( 4 x 14 )

4 x 14 = 56

therefore your answer is 56

77julia77 [94]4 years ago
3 0

Answer: B 56

Step-by-step explanation:

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suter [353]

Answer:

option 3 is neither option 2 is complementary the first is supplementary

Step-by-step explanation:

Complementry is any angle that is an angle below 90 degrees and supplementary is any angle higher than 90 degrees but less then or equal to 180 degrees

6 0
4 years ago
What is the least common multiple of 2, 10 and 6
Lera25 [3.4K]
The least common multiple<span> (</span>LCM<span>) of numbers is the smallest number that they all can divide evenly into.

2 = 1 </span>× 2

10 = 1 × 2 × 5

6 = 1 × 2 × 3

Hence, the least common multiple is 1 × 2 = 2.
7 0
4 years ago
Read 2 more answers
SOMEONE PLEASE HELP ME ASAP
sergij07 [2.7K]

Answer:

(0, 32.1) (1, 29.8)

(29.8 - 32.1)/(1-0)= -2.3/1= -2.3

y - 32.1 = -2.3(x - 0)

y - 32.1 = -2.3x + 0

y = -2.3x + 32.1

Step-by-step explanation:

It is linear

work is shown above

7 0
3 years ago
g what is the 95% confidence interval a researcher wishes to compare the average amount of time spent in extracurricular
Serggg [28]

Complete question is;

A researcher wished to compare the average amount of time spent in extracurricular activities by high school students in a suburban school district with that in a school district of a large city. The researcher obtained a simple random sample of 60 high school students in a large suburban school district and found the mean time spent in extracurricular activities per week to be six hours with a standard deviation of three hours. The researcher also obtained an independent simple random sample of 40 high school students in a large city school district and found the mean time spent in extracurricular activities per week to be four hours with a standard deviation of two hours. Let x¯1 and x¯2 represent the mean amount of time spent in extracurricular activities per week by the populations of all high school students in the suburban and city school districts, respectively. Assume two-sample t procedures are safe to use?

what is the 95% confidence interval a researcher wishes to compare the average amount of time spent in extracurricular?

Answer:

CI = (0.755, 3.245)

Step-by-step explanation:

For SRS of 60;

Mean: x1¯ = 6

Standard deviation: s1 = 3

For SRS of 40;

Mean: x2¯ = 4

Standard deviation; s2 = 2

Critical value for the confidence interval of 95% is: t = 1.96

Formula for the CI is;

CI = (x¯1 - x¯2) ± t√[(s1²/n1) + ((s2)²/n1)]

Plugging in the relevant values, we have:

CI = (6 - 4) ± 1.96√[(3²/60) + ((4)²/40)]

CI = 2 ± 1.96√[(3²/60) + ((4)²/40)]

CI = 2 ± 1.96√0.55

CI = 2 ± 1.245

CI = [(2 - 1.245), (2 + 1.245)]

CI = (0.755, 3.245)

5 0
3 years ago
0.5(x^4 − 9) + 17 <br><br> Combine like terms.
galben [10]

Hello from MrBillDoesMath!

Answer:

0.5 x^4 + 12.5



Discussion:

Only the constant terms are "like" and can be combined. Nothing combines with x^4.

0.5 ( x^4 - 9) + 17 =

0.5 x^4 -  0.5 (9) + 17 =               as 0.5(9) = 4.5

0.5x^4  -  4.5 + 17 =

0.5 x^4 + 12.5


Thank you,

MrB

7 0
3 years ago
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