complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Multiply 0.25 by 2 and you get 0.50
Don’t know the answer nor the explanation ! Same situation as of yours !
Angle B is HALF of the sum of the two angles it intercepts.
Since it intercepts 48 and 142 degrees, simply add them add divide by 2:
B = (48 + 142)/2
B = 190/2
B = 95
The measure of angle B is 95 degrees.
-T.B.
Answer:
no solution
Step-by-step explanation:
y = -2x + 3
6x + 3y = -3
the substitution method means you plug one equation into the next, because the first equation gives us a solution for y we can go ahead and plug that into y of the second equation
6x + 3(-2x + 3) = -3
6x - 6x + 9 = -3
9 = -3
which is false meaning that there are no solutions and the lines don't touch at any point
