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3 years ago

Find the missing coefficient. -___________ y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0

Mathematics

2 answers:

Luden [163]3 years ago

7 0

y = 0
Hope this helps! (:

Allushta [10]3 years ago

7 0

Answer:

Missing Coefficient is -8

Step-by-step explanation:

We are given, _y² - [ -5y - y( -7y -9) ] - [ -y(15y + 4) ] = 0

We have to find missing value.

let missing value be a

ay² - [ -5y - y( -7y - 9) ] - [ -y(15y + 4) ] = 0

ay² - [ -5y + 7y² + 9y ] - [ -15y² - 4y ] = 0

ay² - [ 7y² + 4y ] + 15y² + 4y = 0

ay² - 7y² - 4y + 15y² + 4y = 0

ay² - 7y² + 15y² + 4y - 4y = 0

( a - 7 + 15 )y² = 0

RHS can be written as

( a - 7 + 15 )y² = 0.y²

Now comparing coefficient of both sides we get,

a - 7 + 15 = 0

a + 8 = 0

a = -8

Therefore, Missing Coefficient is -8

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Complete the tables of value for f(x) and g(x)

tresset_1 [31]

Answer:

Step-by-step explanation:

just multiply or add or divide to get your answer

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3 years ago

A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556

MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

$\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}$

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then, $\overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560$

Now, $\sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76$

Then, $\sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76$

Hence, the standard deviation of his measurements = 2.76 g

6 0

3 years ago

Please answer this question!! 30 points and brainliest!

Alexeev081 [22]

2x(-5x-3)

2x(-5x)= -10x and 2x(-3)= -6x

= -10x sq - 6x

-10x is sq bc you are multiplying the same variable twice

5 0

3 years ago

Which statement would make this true<br> |-27|_____|-45|<br> A.greater<br> B.equal<br> C.less

Effectus [21]

Answer:

I would say the answer is A.

Step-by-step explanation:

Hope it helps :)

7 0

2 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

5 0

2 years ago