Answer: 
This is the same as writing y = (1/2)x + 3
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Explanation:
Two points on the blue line are (0,3) and (2,4)
To go from the left point to the right, we go up 1 and over to the right 2.
Slope = rise/run = 1/2
Or we can use the slope formula to get the same value
m = (y2-y1)/(x2-x1)
m = (4-3)/(2-0)
m = 1/2
The y intercept is b = 3 because this is the location on the vertical y axis where the blue line crosses. This is the location (0,3).
With m = 1/2 and b = 3, we go from y = mx+b to y = (1/2)x + 3
On a piece of paper, that would look like the equation 
Answer:
yes
Step-by-step explanation:
if they continue both lines they would not meet.
The numerical value of the mean voltage is 25.47 V
To find the numerical value of the mean voltage, V of V(t) = 40 sin(t), we integrate V(t) with respect to t over the interval [0.π]
So,
![V = \frac{1}{\pi } \int\limits^\pi _0 {V(t)} \, dt \\V = \frac{1}{\pi } \int\limits^\pi _0 {40sint} \, dt \\V = \frac{1}{\pi } [-40cost]_{0}{\pi } \\V = \frac{1}{\pi } -[40cos\pi - 40cos0]\\\\V = \frac{1}{\pi } (-[40 X (-1) - 40 X 1})\\V = -\frac{1}{\pi } [-40 - 40]\\V = \frac{80}{\pi } \\V = 25.465 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7BV%28t%29%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7B40sint%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40cost%5D_%7B0%7D%7B%5Cpi%20%7D%20%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20-%5B40cos%5Cpi%20%20-%2040cos0%5D%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%28-%5B40%20X%20%28-1%29%20-%2040%20X%201%7D%29%5C%5CV%20%3D%20-%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40%20-%2040%5D%5C%5CV%20%3D%20%5Cfrac%7B80%7D%7B%5Cpi%20%7D%20%5C%5CV%20%3D%2025.465%20V)
V ≅ 25.47 V
So, the numerical value of the mean voltage is 25.47 V
Learn more about mean volatage here:
brainly.com/question/17928028
The answer is A. Subtract the five on both sides and you end up with A :)
Answer: Like the angles BAC (56°) and BDC has the same arc BC in the circumference, these angles must be congruent, then angle BDC must be equal to 56°.