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patriot [66]
3 years ago
15

Describe three different methods to solve x²- x - 56 =0

Mathematics
1 answer:
Vika [28.1K]3 years ago
5 0
Methods: 1) Factoring 2) Complete the square 3) Quadratic form
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An airplane traveled 700 kilometers in two hours during a trip. What was the average speed of the plane during the trip?
Igoryamba

9514 1404 393

Answer:

  350 km/h

Step-by-step explanation:

Speed = distance/time

speed = (700 km)/(2 h) = 350 km/h

8 0
3 years ago
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
3 years ago
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
What is the answer for this question
evablogger [386]

-3: y = -2 * (-3) - 7 = 6 - 7 = -1

0: y = -2 * 0 - 7 = -7

3: y = -2 * 3 - 7 = -6 - 7 = -13

6: y = -2 * 6 - 7 = -12 - 7 = =-19

6 0
3 years ago
Sebastian received 200 in holiday presents.He deposited 70% of that money in his bank account. How much did he put his bank acco
VashaNatasha [74]

Answer:

$140 in the bank account

Step-by-step explanation:

0.70 (or 70%) of $200 = 140

70% of 100 = $70

$70 x 2 = $140

7 0
3 years ago
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