They are counting by twos.
2,4,6,8,10,12,14,16,18,20,etc
The required expressions are both equations 1 and 2 as shown:

.... 2
Complementary angles are angles that sum up to 90 degrees. For instance, and A and B are complementary if A + B = 90.
According to the question, if two complementary angles have measures of s and t then:

Twice of 's' is expressed as 
If t is less than twice s, this can be expressed as
.... 2
The required expressions are both equations 1 and 2 as shown:

.... 2
Learn more on word problems leading to simultaneous equations here: brainly.com/question/14294864
In the inverse we replace the place of x by y .
![g(x) = \sqrt[3]{x} - 3 \\ \\ x = \sqrt[3]{y} - 3 \\ \sqrt[3]{y} = x + 3 \\ y = {(x + 3)}^{3} \\ y = {(x + 3)}^{2} (x + 3) \\ y = ({x}^{2} + 6x + 9)(x + 3) \\ \\ y = {x}^{3} + 6 {x}^{2} + 9x + 3 {x}^{2} + 18x + 27 \\ \\ y = {x}^{3} + 9 {x}^{2} + 27x + 27 \\ \\ \\ g(x)^{ - 1} = {x}^{3} + 9 {x}^{2} + 27x + 27](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20%20-%203%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7By%7D%20%20-%203%20%5C%5C%20%20%5Csqrt%5B3%5D%7By%7D%20%20%3D%20x%20%2B%203%20%5C%5C%20y%20%3D%20%20%7B%28x%20%2B%203%29%7D%5E%7B3%7D%20%20%5C%5C%20y%20%3D%20%20%7B%28x%20%2B%203%29%7D%5E%7B2%7D%20%28x%20%2B%203%29%20%5C%5C%20y%20%3D%20%20%28%7Bx%7D%5E%7B2%7D%20%20%2B%206x%20%2B%209%29%28x%20%2B%203%29%20%5C%5C%20%5C%5C%20%20y%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%206%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20%2B%203%20%7Bx%7D%5E%7B2%7D%20%20%2B%2018x%20%2B%2027%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%209%20%7Bx%7D%5E%7B2%7D%20%20%2B%2027x%20%2B%2027%20%5C%5C%20%20%20%5C%5C%20%5C%5C%20g%28x%29%5E%7B%20-%201%7D%20%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%209%20%7Bx%7D%5E%7B2%7D%20%20%2B%2027x%20%2B%2027%20)
I hope I helped you^_^
Answer:

Step-by-step explanation:
For this, you check to see if any of these variables are the same. There are two x's, and 2 y's. So, you have to multiply x and x, which gives you 2x, and since you multiply the y's it will give you y^2.
So the answer will be 
Answer:
Step-by-step explanation:
The sin(30) = 1/2
The sin(30) = 1/2 = opposite / hypotenuse
Opposite = 7
hypotenuse = opposite / sin(30)
hypotenuse = 7 / (1/2) = 7 *2 / 1 = 14
The long side can be found using the Pythagorian Theorem.
a^2 + b^2 = c^2
a = 7
b = ?
c = 14
14^2 = 7^2 + b^2
196 - 49 = b^2
147 = c^2
147 = 3*7 *7
sqrt(b^2) = sqrt(3*7*7)
b = 7 sqrt(3)