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kherson [118]
3 years ago
12

Ronald scored 34 points in a basketball game. In the first quarter he scored x points and in the second quarter, he scored 4 mor

e than half of the points he scored in the first quarter. If he did not play for the rest of the game, how many points did he score in the second quarter?
Mathematics
1 answer:
shutvik [7]3 years ago
7 0

Answer:

He scored 14 points in the second quarter.

Step-by-step explanation:

x = first quarter, y = second quarter

x + y = 34

y = 0.5(x) + 4

Therefore,

   x + [0.5(x) + 4] = 34

or           1.5x + 4 = 34

or                 1.5x = 30

or                     x = 20

So,

   20 + y = 34

or         y = 14

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Please answer question 4
dangina [55]

They reject if the pie is more than 3.2oz from 28oz.

The scale shows positive number if its more than 28oz.

The scale shows negative number if its less than 28oz.

The scale shows zero if its 28oz.

A .  Scale reads -2.8oz which means less than 28oz, So accepted.

B.   Scale reads 3.5oz which means 3.5oz more than 28oz. So rejected.

C.   Scale reads -3.3oz which means less  than 28oz, So accepted.

D.   Scale reads 28oz which means more than 28oz, So rejected.

3 0
3 years ago
Solve for x: 2(x 3)2 − 4 = 0 Round your answer to the nearest hundredth. X = 4. 41, 1. 59 x = 1. 34, 5. 24 x = −1. 34, −5. 24 x
gladu [14]

The two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

ax^2+bx+c=0

Here, (<em>a,b,c</em>) are the real numbers and <em>x </em>is the variable.

To find the value of x, the following formula is used,

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The given equation is,

2(x+ 3)^2 - 4 = 0

To solve this equation, we need to apply some mathematical operations over it. Let's start with opening the brackets.

2(x+ 3)^2 - 4 = 0\\2(x^2+6x+9)-4=0\\2x^2+12x+14-4\\2x^2+12x+12=0\\x^2+6x+7=0

On comparing with standard equation we get,

a=1, b=6, c=7

Put this values in the above formula,

x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=-4.41,-1.59

Hence, the two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

Learn more about the quadratic equation here;

brainly.com/question/1214333

5 0
3 years ago
Im confused on this one !
Alex787 [66]

I believe that it would be the first one. They are looking for the distance from the y-axis, so the x value doesnt matter. 6 is 6 units away from the y-axis, and -6 is also 6 units away from the y-axis. Hope I helped!

6 0
3 years ago
How should this problem be solved?(a3)2
baherus [9]
You can not "solve" this, so to speak, rather simplify this expression. Take the "2" and multiply that by the "a" and the "3" in the parentheses. You will then have the simplified answer of: 2a times 6. 
Hope that helps!
8 0
4 years ago
Necesito esto para hoy y no entiendo
BaLLatris [955]

Operación: (+6)-(3). Piso Final: +3

Inicial: +8 Operación: (+8)+(+1) Piso final: +9

Inicial: +10 Operación: (+10)-(4) Piso final: +6

3 0
3 years ago
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