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3 years ago

Find the least common multiple of 8c4 and 6c2 .

1 answer:

6 0

The least common multiple is the smallest term that can be divided to both terms without any remainder. For the two terms 8c^4 and 6c^2, you can determine it into two part. First, you find the LCM for 8 and 6. You find the prime number that is common between the two. That would be 2. For the variables c^4 and c^2, the 'prime variable' is c. Therefore, the least common multiple for 8c^4 and 6c^2 is 2c.

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Joe is building a fort for his little brother out of boxes. He is wondering how much room there will be inside the fort. How muc

STatiana [176]

Answer:

0.5 m³

Step-by-step explanation:

Volume is the combination of 2 volumes

1. Dimensions: 0.5 m, 05 m and 1.5 - 1 = 0.5 m
2. Dimensions: 1 m, 0.5 m and 0.75 m

So the volume is:

0.5*0.5*0.5 + 1*0.5*0.75 = 0.5 m³

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3 years ago

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fenix001 [56]

Answer:

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Step-by-step explanation:

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3 years ago

Calculate the area of a parallelogram with a base of 3 feet and a height of 1.2 feet

Fantom [35]

Answer: 3.6

Step-by-step explanation: 3x1.2= 3.6

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3 years ago

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In the data set below, what are the lower quartile, the median, and the upper quartile?

Studentka2010 [4]

The median, upper and lower quartiles of the data set are:

Lower Quartile = 46

Median = 49

Upper Quartile = 90

<h3>What is the Median?</h3>

The center value or middle value of a data set is the median.

<h3>What are the Upper and Lower Quartiles?</h3>

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Order the data set given as:

32, 46, 49, 49, 77, 90, 96

Lower Quartile = 32, (46), 49, 49, 77, 90, 96 = 46

Median = 32, 46, 49, (49,) 77, 90, 96 = 49

Upper Quartile = 32, 46, 49, 49, 77, (90,) 96 = 90

Learn more about the Median, Upper and Lower Quartiles on:

brainly.com/question/15572643

3 0

2 years ago

The question is in the image below.

sineoko [7]

Answer:

The Recursive Formula for the sequence is:

$\:a_n=\frac{1}{5}\left(a_{n-1}\right)$ ; a₁ = 125

Hence, option D is correct.

Step-by-step explanation:

We know that a geometric sequence has a constant ratio 'r'.

The formula for the nth term of the geometric sequence is

$a_n=a_1\cdot r^{n-1}$

where

aₙ is the nth term of the sequence

a₁ is the first term of the sequence

r is the common ratio

We are given the explicit formula for the geometric sequence such as:

$a_n=125\left(\frac{1}{5}\right)^{n-1}$

comparing with the nth term of the sequence, we get

a₁ = 125

r = 1/5

Recursive Formula:

We already know that

a₁ = 125

r = 1/5

We know that each successive term in the geometric sequence is 'r' times the previous term where 'r' is the common ratio.

i.e.

$a_n=ra_{n-1}$

Thus, substituting r = 1/5

$\:a_n=\frac{1}{5}\left(a_{n-1}\right)$

and a₁ = 125.

Therefore, the Recursive Formula for the sequence is:

$\:a_n=\frac{1}{5}\left(a_{n-1}\right)$ ; a₁ = 125

Hence, option D is correct.

3 0

3 years ago