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harkovskaia [24]
3 years ago
10

The ages of four sisters are consecutive even integers. Two times the age of the youngest sister exceeds the oldest sister's age

by 30 years. The equation 2x − (x + 6) = 30 models the age, x, of the youngest sister. What is the age of the oldest sister?
Mathematics
2 answers:
ruslelena [56]3 years ago
7 0

Answer:

42 years

Step-by-step explanation:

2x − (x + 6) = 30

x − 6 = 30

x = 36

Therefore,

<em>x + 6 = 36 + 6 = 42</em>

S_A_V [24]3 years ago
5 0

Alright, lets get started.

The ages of all four sisters will be = x, x+2, x+4, x+6

As per given in question, two times of youngest sister age exceeds the oldest sister age by 30 means

2x - 30 = (x+6)

Simplifying the equation

2x - (x+6) = 30

2x - x - 6 = 30

x = 36

So this is the age of youngest sister.

So, age of oldest sister will be x + 6 = 36 + 6 = 42

Hene the age of oldest sister is 42 years.   :  Answer

Hope it will help :)


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Answer:

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Step-by-step explanation:

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6 0
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Let the sample size of leg strengths to be 7 and the sample mean and sample standard deviation be 630 watts and 32 watts, respec
Colt1911 [192]

Answer:

a. There is_<u><em>sufficient</em></u> evidence that the leg

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b. Power of test = 1- β=0.2066

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Step-by-step explanation:

We formulate the null and alternative hypotheses as

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Critical value for a right tailed test with 6 df is 1.9432

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The test statistic used here is

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P- value = 0.0023890 > ∝ reject the null hypothesis.

so it lies between 0.010 < P-value < 0.025

b) Power of test if true strength is 610 watts.

For  a right tailed test value of z is = ± 1.645

P (type II error) β= P (Z< Z∝-x- x`/ s/√n)

Z = x- x`/ s/√n

Z= 610-630 / 32 / √7

Z=0.826

P (type II error) β= P (Z< 1.645-0.826)

= P (Z> 0.818)

= 0.7933

Power of test = 1- β=0.2066

(c)

true mean = 610

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standard deviation= 32

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Zβ= 1.282

Sample size needed

n=( (Z∝ +Zβ )*s/ SE)²

n=  ((1.645+1.282) 32/ 10)²

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7 0
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​

).

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2

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=4

y=

2

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​

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