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salantis [7]
3 years ago
8

Robinson's doughnut factory produces 18,000 doughnuts every day. they have a fleet of 12 delivery trucks. if the doughnuts are d

ivided evenly, how many doughnuts will be loaded onto each truck?
Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0
1,500 doughnuts will be added onto each truck. To get this answer, just simply divide the amount of doughnuts by the amount of trucks.

18,000÷12= 1,500.

Hope this helps!
vazorg [7]3 years ago
6 0
1500 for apex ....☁️☁️☁️
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Answer:

1.  χ² = <u>  15.3902 </u>

2. The p value is :_____.a. less than .005

3.  Conclusion

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4. The percentages of employees

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Large %= 88/100= 0.88

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0: the employee health insurance coverage is independent of the size of the company

against the claim

Ha: the employee health insurance coverage is not independent of the size of the company

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

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which has an approximate chi square distribution with ( 3-1) (2-1)=  2 d.f

4) Computations:

Under H0 , the observed frequencies are :

Observed       Expected E        (O-E)         (O-E)²             (O-E)²/E

33                   42                      -9               81                    1.928  

68                  63                         5              25                  0.3968

88                  84                         4               16                  0.1904

17                    8                           9              81                  10.125

7                     12                          -5             21                    1.75

<u>12                    16                         -4              16                     1              </u>

<u>                                                                                           15.3902    </u>

Expected Values are calculated using the formula :

Row Total * Column Total / sample size

E1= (33+17) (33+ 68+88)/ 50+75+100= 42

E4= (33+17) (17+ 7+ 12)/ 50+75+100=8

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E5= (68+7)  (17+ 7+ 12)/ 50+75+100= 12

E3= (88+12) (33+ 68+88)/ 50+75+100= 84

E6= (88+12)  (17+ 7+ 12)/ 50+75+100= 16

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The calculated χ² = <u>  15.3902    </u>falls in the critical region χ² ≥  5.99  so we reject the null hypothesis that the employee health insurance coverage is NOT independent of the size of the company.

2. The p value is :_____.

a. less than .005

The p-value is .000385.

3.  Conclusion

a. health insurance coverage is not independent of the size of the company

4. The percentages of employees

Small %=   33/50= 0.66

Medium %= 68/75 = 0.91

Large %= 88/100= 0.88

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