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3 years ago

Adding & subtracting fractions

2 answers:

7 0

<span>Before you can add or subtract fractions with different denominators, you must first find equivalent fractions with the same denominator, like this:
<span>Find the smallest multiple (LCM) of both numbers.
<span>Rewrite the fractions as equivalent fractions with the LCM as the denominator.</span></span></span>
Hope i helped!

Travka [436]3 years ago

7 0

When you add or subtract fractions, the denominators must be the same. Then you add or subtract the numerators and have that same denomenator

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20 points!! Pls help

Studentka2010 [4]

Answer:

Step-by-step explanation:

-x-3=y, therefore x = -y-3

-3x - 8y = 4

Find the value of y

Substitute the x in -3x - 8y = 4 with -y-3

We get

-3·(-y-3) - 8y = 4

3y + 9 - 8y = 4

-5y = 4-9

-5y = -5

_______________

Find the value of x

x = -y-3

x = -1-3

_______________

Answer (x, y) =

_____________________

#IndonesianPride - kexcvi

5 0

3 years ago

Read 2 more answers

Triangle DEF has sides of length x, x+3, and x−1. What are all the possible types of DEF?

Natalija [7]

Triangle DEF is scalene

Must click thanks and mark brainliest

6 0

3 years ago

4a+6b=10<br> 2a-4b=12<br><br> what does 12a =?

Usimov [2.4K]

If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).

In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)

2a - 4b = 12 => (divide by two and move the b's to the other side)

a = 6 + 2b. (plug this one into the top equation)

4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1

a = 6 + -2 = 4.

So a=4 and b=-1.

4 0

3 years ago

Help I don’t get it at all

Naily [24]

The answer to your question is n is equal to 70

5 0

3 years ago

Read 2 more answers

Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

8 0

3 years ago